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amm1812
2 years ago
12

100x^2-9 factored completely

Mathematics
1 answer:
Ne4ueva [31]2 years ago
7 0

Answer:

Step-by-step explanation:

this is the difference of two squares,  which there is a formula for

(a+b)(a-b)  

100x^{2}-9

rewrite into squares

(10x)^{2} - 3^{2}

then a = 10x

and b = 3

(10x + 3 )(10x - 3 )

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I need help on how to solve this so anything is good :)
DanielleElmas [232]

Answer:

STUV is a square

Step-by-step explanation:

segment length² = (x-x₁)² + (y-y₁)²

ST²: (-9 - 1)2 + (14 - 10)² = (-10)² + 4² = 116   (the rest follow this formula)

TU² = 116    TV² = 232    SU² = 232   SV² = 116   UV² = 116

ST = TU =SV = UV  (4 sides congruent)

TV = SU  (diagonal equal)

This is a square

4 0
2 years ago
Question 1 (1 point) Question 1 Unsaved
QveST [7]
en la cocina (where is the dishwasher? the kitchen)
7 0
2 years ago
What's the surface area of this figure? (figure shown on picture)
KIM [24]

Answer:

800 in²

Step-by-step explanation:

Let’s find the area of all the shapes in the net.

10 · 10 = 100

100 · 2 = <u>200</u>

15 · 10 = 150

150 · 4 = <u>600</u>

200 + 600 = <u><em>800</em></u>

3 0
2 years ago
A farmer wants to fence in a rectangular field that encloses 3600 square feet. One side of the field is along a river and does n
andriy [413]

Answer:

C(x) = \$3.50(\frac{x^2+7200}{x})

Step-by-step explanation:

Data provided in the question:

Area of the field = 3600 square feet

Fencing charges = $3.50 per foot

Let the side along the river be 'x' feet and the other side of the 'B'

now,

Area of rectangle = Bx = 3600 square feet

or

B = \frac{3600}{x} feet

and total length to be fenced = x + 2B

therefore,

Total cost of fencing = Fencing charges × total length to be fenced

or

Total cost of fencing = $3.50 × ( x + 2B )

substituting the value of B from (1)

Total cost of fencing, C(x) = \$3.50(x+2\times\frac{3600}{x})

or

C(x) = \$3.50(\frac{x^2+7200}{x})

4 0
3 years ago
What is the domain and range of the following functions? Number 1 please
MrMuchimi
Answers:
Part 1 (the ovals)
Domain = {-6,-1,1,5,7}
Range = {-4,-1,2,4}
-------------------
Part 2 (the table)
Domain = {1,-3,-2}
Range = {-2,5,1}
-------------------
Part 3 (the graph)
Domain = {1, 2, 3, 4, 5, 6}
Range = {-1, 0, 1, 2, 3, 6}

===============================================

Explanation:

Part 1 (the ovals)
The domain is the set of input values of a function. The input oval is the one on the left. 
All we do is list the numbers in the input oval to get this list: {-6,-1,1,5,7}
The curly braces tell the reader that we're talking about a set of values.
So this is the domain.

The range is the same way but with the output oval on the right side
List those values in the right oval and we have {-4,-1,2,4}
Which is the range. That's all there is to it.

------------------------------

Part 2 (The tables)

Like with the ovals in part 1, we simply list the input values. The x values are the input values. Notice how this list is on the left side to indicate inputs.
So that's why the domain is {1, -3, -2}. Optionally you can sort from smallest to largest if you want. Doing so leads to {-3, -2, 1}

The range is {-2,5,1} for similar reasons. Simply look at the y column

Side Note: we haven't had to do it so far, but if we get duplicate values then we must toss them. 
------------------------------
Part 3 (the graph)

Using a pencil, draw vertical lines that lead from each point to the x axis. You'll notice that you touch the x axis at the following numbers: 1, 2, 3, 4, 5, 6
So the domain is the list of those x values (similar to part 2) and it is {1, 2, 3, 4, 5, 6}

Erase your pencil marks from earlier. Draw horizontal lines from each point to the y axis. The horizontal lines will arrive at these y values: -1, 0, 1, 2, 3, 6
So that's why the range is {-1, 0, 1, 2, 3, 6}

5 0
3 years ago
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