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kykrilka [37]
4 years ago
7

Which statements prove that line R is perpendicular to line P ?

Mathematics
1 answer:
oksian1 [2.3K]4 years ago
7 0

Answer: Line R and Line P are perpendicular because they intersect at a point and create a pair of equal angles.

Step-by-step explanation:

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Answer:

according to the equation it is 158.330917...

Step-by-step explanation:

put w as 64 and solve for t

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The sum of three numbers is 7. One of the numbers is one more than the sum of the other two numbers. It is also four times the d
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The only numbers I could think of would be 1, 2, and 4 because 4 is greater than 3 (2+1) and four times greater than 1 (2-1)
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Pls help asappppppp it is very important I need it pls
Volgvan

Given:

The graph of a proportional relationship.

To find:

The constant of proportionality, the value of y when x is 24 and the value of x when y is 108.

Solution:

If y is directly proportional to x, then

y\propto x

y=kx             ...(i)

Where, k is the constant of proportionality.

The graph of proportional relationship passes through the point (5,15).

Substituting x=5 and y=15 in (i), we get

15=k(5)

\dfrac{15}{5}=k

3=k

Therefore, the constant of proportionality is 3.

Substituting k=3 in (i) to get the equation of the proportional relationship.

y=3x              ...(ii)

Substituting x=24 in (ii), we get

y=3(24)

y=72

Therefore, the value of y is 72 when x is 24.

Substituting y=108 in (ii), we get

108=3x

\dfrac{108}{3}=y

36=y

Therefore, the value of x is 36 when y is 108.

5 0
3 years ago
O is the centre of the circle, EF is a tangent, angle BCE = 28°, angle ACD = 31°
andriy [413]

Answer

a. 28˚

b. 76˚

c. 104˚

d. 56˚

Step-by-step explanation

Given,

∠BCE=28°  ∠ACD=31°  &  line AB=AC .

According To the Question,

  • a. the angle between a chord and a tangent through one of the end points of the chord is equal to the angle in the alternate segment.(Alternate Segment Theorem) Thus, ∠BAC=28°

  • b. We Know The Sum Of All Angles in a triangle is 180˚, 180°-∠CAB(28°)=152° and ΔABC is an isosceles triangle, So 152°/2=76˚

        thus , ∠ABC=76° .

  • c. We know the Sum of all angles in a triangle is 180° and opposite angles in a cyclic quadrilateral(ABCD) add up to 180˚,

Thus, ∠ACD + ∠ACB = 31° + 76° ⇔ 107°

Now, ∠DCB + ∠DAB = 180°(Cyclic Quadrilateral opposite angle)

∠DAB = 180° - 107° ⇔ 73°

& We Know, ∠DAC+∠CAB=∠DAB ⇔ ∠DAC = 73° - 28° ⇔ 45°

Now, In Triangle ADC Sum of angles in a triangle is 180°

∠ADC = 180° - (31° + 45°)  ⇔  104˚

   

  • d. ∠COB = 28°×2 ⇔ 56˚ , because With the Same Arc(CB) The Angle at circumference are half of the angle at the centre  

For Diagram, Please Find in Attachment  

4 0
3 years ago
Ben solved an equation as shown below, Equation 2 (-3×+1)=9×-8. what did he do wrong. step1. -6×+2=9×- 8. step2. -6×+9×=-8+2. st
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He just switched sides of the variables and numbers. Instead if adding the opposite.
8 0
3 years ago
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