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3 years ago

The principal P is borrowed and the loan's future value A at time t is given. Determine the loan's simple interest rate r.

Mathematics

1 answer:

Virty [35]3 years ago

8 0

A = P + SI

A-P = SI

5425-5000 = 425

THEREFORE THE SIMPLE INTRESTE IS $425

SI = PTR/100

425 = 5000×1×R/100

425×100/5000×1=R

425×100÷5,000×1 = 8.5%

THEREFORE THE RATE IS 8.5%

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Please help me solve for x

densk [106]

Answer:

A. x=16

Step-by-step explanation:

Similar triangles/ratios

1. Substitute 2x + 7 = 39, 4x + 1 = 65

2. Find size ratio between the two figures, 5:3

3. Check for similarity - 39 x 5/3 = 65

4 0

3 years ago

A line passes through the points (–5, 2) and (10, –1). Which is the equation of the line?

LenKa [72]

We have y - 2 = m(x + 5), where m = (-1 - 2)/(10 + 5) = -3/15 = -1/5;
Then y - 2 = (-1/5)(x + 5);
5y - 10 = (-1)(x + 5);
5y - 10 = -x - 5;
x + 5y - 5 = 0 is the equation of the line.

3 0

3 years ago

Higher Order Thinking Lemmy walked 3 1/2 miles on Saturday and miles 4 3/4 on Sunday. Ronnie walked 5 3/8 miles on Saturday. Who

julsineya [31]

Answer:

Lemmy ; 2 7/8 miles

Step-by-step explanation:

Given that :

Distance walked by Lemmy:

Saturday = 3 1/2 miles

Sunday = 4 3/4 miles

Total distance walked by Lemmy:

3 1/2 + 4 3/4

7/2 + 19/4

(14 + 19) / 4

33 / 4

= 8 1/4

Miles walked by Ronnie : 5 3/8

Lemmy walked farther because : 8 1/4 > 5 3/8

Number of distance walked farther than Ronnie :

8 1/4 - 5 3/8

33/4 - 43/8

(66 - 43) / 8

= 23/ 8

= 2 7/8 miles

4 0

3 years ago

After each soccer practice Scott Runs 4 sprints of 10 yards each complete exclamation to find how many practices it will take fo

Tpy6a [65]

Answer:

Scott will have to do 44 practices

Step-by-step explanation:

Let X be the number of yards per practice.

Let P = number of practice Scott needs to do.

Multiply 20 yards by 4 sprints

X = 20yards × 4 sprints = 80 yards

Number of yards he had to sprint per practice will be:

1 mile = 1760 yards

Converting from miles to yards

X = 1760 × 2 miles = 3520 yards

Number of practice,P Scott need to do = (3520/80)yards

Number of Practice,P = 44

5 0

4 years ago

Read 2 more answers

Ming kept track of her puppy Sampson's weight gain over a three-month time period. He was six weeks old on November 15 and weigh

Kobotan [32]

Answer:

Sampson gains 3.967 kilograms from November to February.

Step-by-step explanation:

Given:

Actual Weight on November 15 = 2.49 kg

On December 15, he weighed 1020 grams more

Since 1000 grams = 1 kg

Weight on December 15 = 1020 grams = 1.2 kg

Hence Weight gained from November 15 to December 15 = 1.2 kg

On January 15, he had gained another 2200 grams

Weight on January 15 = 2200 grams = 2.2 kg

Hence Weight gained from December 15 to January 15 = 2.2 kg

On February 15, he had only gained 0.567 kilograms.

Weight on February 15 = 0.567 kg

Hence Weight gained from January 15 to February 15 = 2.2 kg

Total weight gained from November to February = Weight gained from November 15 to December 15 + Weight gained from December 15 to January 15 + Weight gained from January 15 to February 15

Total weight gained from November to February = $1.2+2.2+0.567 = 3.967 \ kg$

Hence Sampson gained total weight of 3.967 kg from November to February.

4 0

3 years ago