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3 years ago

The principal P is borrowed and the loan's future value A at time t is given. Determine the loan's simple interest rate r.

Mathematics

1 answer:

Virty [35]3 years ago

8 0

A = P + SI

A-P = SI

5425-5000 = 425

THEREFORE THE SIMPLE INTRESTE IS $425

SI = PTR/100

425 = 5000×1×R/100

425×100/5000×1=R

425×100÷5,000×1 = 8.5%

THEREFORE THE RATE IS 8.5%

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Plz help me I need because it’s one of my last assignments for school

Brums [2.3K]

Step-by-step explanation:

straight line = 180 degree

example

1) 2w - 24 + 2w - 40 = 180

4w = 180 + 24 + 40

4w = 244

w = 244/4

.......

2) 13n - 11 +(-9 + 12n)

13n - 11 -9 + 12n = 180

25n -20 = 180

25n = 180 + 20

25n = 200

n = 200/25

.........

8 0

2 years ago

Steven has some money. If he spends $9.00, then he will have 3 5of the amount he started with

docker41 [41]

$1.80 if the question was ( he would have 3/5 of the amount he started with)

7 0

2 years ago

For a function p(x)= x^2-9, what is the inverse function for the domain [0, infinity\

kkurt [141]

An inverse function is a function that reverses another function, so we have a function called:

$p(x)$

Then, the inverse function will be as follows:

$p^{-1}(x)$

Given that $y = p(x)$ , we need to isolate x in terms of y:

$y = x^{2} -9$
∴ $y+9 = x^{2}$

So:

$x=+\sqrt{y+9}$ and $x=-\sqrt{y+9}$

therefore, exchanging variables x and y:

$y=+\sqrt{x+9}$ and $y=-\sqrt{x+9}$
$p^{-1}(x)=+\sqrt{x+9}$ and $p^{-1}(x)=-\sqrt{x+9}$

Which are the figures shown below.

7 0

3 years ago

Please help, I dont know how to do this

Mrrafil [7]

Answer:

$\frac{y-2}{4}$

Step-by-step explanation:

Let's start by factoring everything:

$\dfrac{\frac{y^2+y}{y^2-2y}}{\frac{4y+4}{y^2-4y+4}}=$

$\dfrac{\frac{y(y+1)}{y(y-2)}}{\frac{4(y+1)}{(y-2)^2}}=$

Now, you can cancel out some terms:

$\dfrac{\frac{y+1}{y-2}}{\frac{4(y+1)}{(y-2)^2}}=$

Now, when you divide a fraction by another fraction, that is the same as multiplying the first fraction by the reciprocal of the second one:

$\frac{y+1}{y-2}\cdot \frac{(y-2)^2)}{4(y+1)}=$

$\frac{y-2}{4}$

Hope this helps!

4 0

3 years ago

20 how much metal is needed to smelt a cubical metal box with outer side 12 inches long if the thickness of its walls should be

guajiro [1.7K]

The volume of the metal box if the box was completely solid (V1), is:

V1=(12 inches)³
V1=1728 inches³

As there are 3 inches of metal on both sides, the widht if the metal box was not completely solid, is:

W=12 inches-(3 inchesx2)
W=6 inches

Then, the volumen of the no solid metal box is:

V2=(6 inches)³
V2= 216 inches³

Therefore, the volume of metal needed to smelt the cubical metal box, is:

V3=V1-V2
V3=1728 inches³-216 inches³
V3=1512 inches³

6 0

2 years ago