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8_murik_8 [283]
3 years ago
8

The world's largest cookie was baked in North Carolina in 2003. Its diameter was 100 feet and it contained about 6,000 pounds of

chocolate chips! If the cookie was a cylinder 1 foot tall, and you wanted to cover it with icing, how many square inches would you have to ice? Use 3.14 for .
Mathematics
1 answer:
Natasha2012 [34]3 years ago
4 0

Answer:

16022 square foot

Step-by-step explanation:

The world's largest cookie was baked in North Carolina in 2003. Its diameter was 100 feet and it contained about 6,000 pounds of chocolate chips! If the cookie was a cylinder 1 foot tall, and you wanted to cover it with icing, how many square inches would you have to ice? Use 3.14 for .

We find the surface area of the cylinder

= 2πr(r + h)

r = Diameter /2 = 100 feet/2

r = 50 feet

h = 1 feet

Hence

2 × 3.14 × 50(50 + 1)

= 16022.122533 square foot

= 16022 square foot

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Please check my answer !! thank you ⭐️
horrorfan [7]
I think your answer is right.
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3 years ago
A(x-b)+bx-c=a+b, when a DOES NOT = -b ; FIND X PLEASE!!! WILL GIVE BRAINLIEST!!
tangare [24]

9514 1404 393

Answer:

  x = (ab +a +b +c)/(a +b)

Step-by-step explanation:

Eliminate parentheses, subtract left terms not containing x, divide by the coefficient of x.

  a(x-b)+bx-c=a+b\\\\ax+bx-ab-c=a+b\\\\x(a+b)=ab+a+b+c\\\\\boxed{x=\dfrac{ab+a+b+c}{a+b}}

6 0
2 years ago
Yassar has purchased a $30,000 car for his business. The car depreciates at 30%
fiasKO [112]

Answer:

A

Step-by-step explanation:

30% of 30000 is 9000, 30000-9000=21000 (1 year)

30% of 21000 is 6300, 21000-6300=14700 (2 years)

30% of 14700 is 4410, 14700-4410= 10290 (3 years)

30% of 10290 is 3087, 10290-3097= 7203 (4 years)

30% of 7203 is 2160.9, 7203-2160.9= 5042.1 (5 years)

5 0
2 years ago
Jason went to the post office and bought both 41-cent stamps and 26-cent postcards and spent $10.28. The number of stamps was 4
Charra [1.4K]
<h3>Jason bought 20 stamps of $0.41 each and 8 postcards of $0.26 each.</h3>

<em><u>Solution:</u></em>

Let stamps be s and postcards be p

Given that,

The number of stamps was 4 more than twice the number of postcards

s = 4 + 2p -------- eqn 1

Jason bought both 41-cent stamps and 26-cent postcards and spent $10.28

41 cent = $ 0.41

26 cent = $ 0.26

Therefore,

s \times 0.41 + p \times 0.26 = 10.28

0.41s + 0.26p = 10.28 --------- eqn 2

Substitute eqn 1 in eqn 2

0.41(4 + 2p) + 0.26p = 10.28

1.64 + 0.82p + 0.26p = 10.28

1.08p = 10.28 - 1.64

1.08p = 8.64

Divide both sides by 1.08

p = 8

Substitute p = 8 in eqn 1

s = 4 + 2(8)

s = 4 + 16

s = 20

Thus Jason bought 20 stamps and 8 post cards

8 0
3 years ago
<img src="https://tex.z-dn.net/?f=%5Cfrac%7Bp%7D%7B5%7D" id="TexFormula1" title="\frac{p}{5}" alt="\frac{p}{5}" align="absmiddle
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Answer:

p ≥ -10

Step-by-step explanation:

first, subtract one from each side to get:

p/5 ≥ -2

lastly, multiply each side by 5

p ≥ -10

6 0
2 years ago
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