5. The expected weight must be greater or equal to 20 pounds but less than 32 pounds.

for every weekend that mia does her household chores her mother gives her $9.for how many weekends does mia have to do her chore

allsm [11]

So, we'll say Mia gets $4.50 a day, since a standard weekend is two days, therefore adding up to $9 a weekend. So if Mia were to do her chores for 4 weekends, she'd have a total of $36 but not $40. So if she were to work an extra weekend, so 5 weekends, she'd have a total of $45. So you can say 5 weekends in order to earn more than $40.

7 0

2 years ago

Helpppp with this math

Ilia_Sergeevich [38]

9514 1404 393

Answer:

x = 8 1/3

Step-by-step explanation:

Put the known values into the equation and solve for x.

f(x) = 3x -1

24 = 3x -1 . . . . . use 24 for f(x)

25 = 3x . . . . . . . add 1 to both sides

25/3 = x . . . . . . divide both sides by 3

The input is x = 8 1/3.

4 0

2 years ago

2. A hemispherical water tank with a volume of 2094 m will have a radius of which

Ivahew [28]

2.5 m jsjwnejdogondbsjsofj find

3 0

2 years ago

1. Let f(x, y) be a differentiable function in the variables x and y. Let r and θ the polar coordinates,and set g(r, θ) = f(r co

Olenka [21]

Answer:

$g_{r}(\sqrt{2},\frac{\pi}{4})=\frac{\sqrt{2}}{2}\\$

Step-by-step explanation:

First, notice that:

$g(\sqrt{2},\frac{\pi}{4})=f(\sqrt{2}cos(\frac{\pi}{4}),\sqrt{2}sin(\frac{\pi}{4}))\\$

$g(\sqrt{2},\frac{\pi}{4})=f(\sqrt{2}(\frac{1}{\sqrt{2}}),\sqrt{2}(\frac{1}{\sqrt{2}}))\\$

$g(\sqrt{2},\frac{\pi}{4})=f(1,1)\\$

We proceed to use the chain rule to find $g_{r}(\sqrt{2},\frac{\pi}{4})$ using the fact that $X(r,\theta)=rcos(\theta)\ and\ Y(r,\theta)=rsin(\theta)$ to find their derivatives:

$g_{r}(r,\theta)=f_{r}(rcos(\theta),rsin(\theta))=f_{x}( rcos(\theta),rsin(\theta))\frac{\delta x}{\delta r}(r,\theta)+f_{y}(rcos(\theta),rsin(\theta))\frac{\delta y}{\delta r}(r,\theta)\\$

Because we know $X(r,\theta)=rcos(\theta)\ and\ Y(r,\theta)=rsin(\theta)$ then:

$\frac{\delta x}{\delta r}=cos(\theta)\ and\ \frac{\delta y}{\delta r}=sin(\theta)$

We substitute in what we had:

$g_{r}(r,\theta)=f_{x}( rcos(\theta),rsin(\theta))cos(\theta)+f_{y}(rcos(\theta),rsin(\theta))sin(\theta)$

Now we put in the values $r=\sqrt{2}\ and\ \theta=\frac{\pi}{4}$ in the formula:

$g_{r}(\sqrt{2},\frac{\pi}{4})=f_{r}(1,1)=f_{x}(1,1)cos(\frac{\pi}{4})+f_{y}(1,1)sin(\frac{\pi}{4})$

Because of what we supposed:

$g_{r}(\sqrt{2},\frac{\pi}{4})=f_{r}(1,1)=-2cos(\frac{\pi}{4})+3sin(\frac{\pi}{4})$

And we operate to discover that:

$g_{r}(\sqrt{2},\frac{\pi}{4})=-2\frac{\sqrt{2}}{2}+3\frac{\sqrt{2}}{2}$

$g_{r}(\sqrt{2},\frac{\pi}{4})=\frac{\sqrt{2}}{2}$

and this will be our answer

3 0

2 years ago

PLS HELP

uysha [10]

Answer:

The option which represents the inequality is option D ; stated as x ≥ 0

Step-by-step explanation:

The marked or dotted position is 0 ; which represents the position of x, when graphing inequality statements, if the point IS SHADED, then it means GREATER THAN EQUAL TO.

Option A is incorrect, the inequality sign is not the same as the direction of the arrow.

Option B, says LESS THAN EQUAL TO, instead of GREATER THAN EQUAL TO

Option C SAYS GREATER THAN instead of GREATER THAN EQUAL TO.

Therefore, Option D is the correct expression which means x is GREATER THAN EQUAL TO.

Learn more : brainly.com/question/24065770

4 0

2 years ago