The question is incomplete, here is the complete question:
A solution is made by mixing 127.g of acetyl bromide and 90.g of heptane . Calculate the mole fraction of acetyl bromide in this solution. Round your answer to 3 significant digits.
<u>Answer:</u> The mole fraction of acetyl bromide is 0.534 and heptane is 0.466
<u>Explanation:</u>
To calculate the number of moles, we use the equation:
.....(1)
- <u>For acetyl bromide:</u>
Given mass of acetyl bromide = 127. g
Molar mass of acetyl bromide = 123 g/mol
Putting values in equation 1, we get:
Given mass of heptane = 90. g
Molar mass of heptane = 100.2 g/mol
Putting values in equation 1, we get:
Mole fraction of a substance is given by:
<u>For acetyl bromide:</u>
<u>For heptane:</u>
Hence, the mole fraction of acetyl bromide is 0.534 and heptane is 0.466