The molar mass of Na₂SO₄ -
2 x Na - 2 x23 = 46
1 x S - 1 x 32 = 32
4 x O - 4 x 16 = 64
total = 46 + 32 + 64 = 142 g/mol
the molarity of solution - 2.0 M
in 1 L of solution , 2.0 moles
Therefore in 2.5 L - 2 mol/L x 2.5 L = 5 mol
then the mass of Na₂SO₄ required = 142 g/mol x 5 mol = 710 g
Answer: The mass of deposited cadmium is 23.9g
Explanation:
According to Faraday Law of Electrolysis, the mass of substance deposited at the electrode is directly proportional to the quantity of electricity passed through the electrolyte.
Faraday has found that the amount of electricity needed to liberate one gm eq. of substance from an electrolyte is 96500C.
Given that
![Cd^+ + SO4^- ==> CdSO4](https://tex.z-dn.net/?f=Cd%5E%2B%20%2B%20SO4%5E-%20%3D%3D%3E%20CdSO4)
time (t) =1.55min *60 =93seconds
Current (I) =221A
Q= It = 221 * 93 =20553C
Molar mass of CdS04 =112.41
96500C will liberate 112.41g
20553C will liberate Xg
Xg= (20553*112.41)/96500
=23.9g
Therefore , the amount of Cd deposited at the electrode is 23.9g
Carbon has an electronic configuration of
1s² 2s² 2p²