Answer:
The correct answer is - alpha particle and positron.
Explanation:
In this question, it is given that, 38^88Sr decays to 34^84Kr, which means there is an atomic number decrease by 4, 38 to 34, and atomic mass decreases by 4 as well 88 to 84.
A decrease in the atomic mass is possible only when there is an emission of the alpha particle as an alpha particle is made of 2 protons and 2 neutrons. If an atom emits an alpha particle, there is a change in atomic number as it decreases by two, and its mass number decreases by four.
So after the emission of an alpha particle, the new atom would be
38^88Sr=> 36^84X => 34^84Kr
so there is also two positron emission that leads to decrease in atomic number by one with each emission:
38^88Sr=> 2^4He+ 36^84X => 36^84X + 2(1^0β+) => 34^84Kr
Positron decay is the conversion of a proton into a neutron with the emission of a positron that causes the atomic number is decreased by one, which causes a change in the elemental identity of the daughter isotope.
Ammonification is performed by bacteria to convert organic nitrogen to ammonia.
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Answer:
T₂ = 478.93 K
Explanation:
Given that,
Initial pressure, P₁ = 178 kPa
Initial temperature, T₁ = 37°C = 310 K
Final pressure, P₂ = 275 kPa
We need to find the new temp of the air in the tire, assuming the volume is constant. We know that,
So, the new temperature is equal to 478.93 K.
1. The option a. 10 mL has the most uncertainty associated with it, because it has only 2 significative figures, while 10.0 mL has three significant figures and 10.00 has four significant figures.
2. The volume of solution that remains is 145.675 mL - 24.2 mL = 121.475 mL rounded to one decimal = 121.5 mL, given that the measure with the most uncerntainty has only one decimal.
