C3H8+3O2--->3CO2+8H
Therefore for every 1:3 there are 3 Carbon dioxides that form. That means find the limiting reactant from the two reactants.
5.5g(1mole C3H8/44.03g of C3H8)=0.1249 moled of C3H8 and if for every one C3H8 we can form three CO2. We can assume 0.3747 miles of CO2 will be produced.
15g of O2(1 mole O2/32g of O2)=0.4685moles O2 and if for every three O2 we can produce three CO2 we may assume a 1:1 ratio.
This means C3H8 will be your limiting reactant. Therefore 0.3747 moles of CO2 will be produced.
0.3747 moles of CO2(48.01 g of CO2/1 mole of CO2)= 17.99 grams of CO2
<span>Two scientists wrote a paper detailing their research and conclusions and submitted it to a scientific journal. Several months later, they received the paper back from the publisher with many comments attached from several fellow scientists. It is either that they revise their study or replicate the study. Most scientists would revisit their work and the findings they had from their research. Most probable if they were successful and the comments of the publisher and the co-scientists were positive they could replicate the study to validate its accountability.<span>
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The reaction would shift to the right (forward).
Balanced chemical reaction: Br2(g) + 2NO(g) ⇌ 2NOBr(g)
According to the Principle the position of equilibrium moves to counteract the change.
The equilibrium shift to the right, so more product (nitrosyl bromide) will be produced. If the product is removed, the reactants will react to produce that product and set equilibrium.
Concentration of the reactants (bromine gas and nitric oxide) is reducing, while concentration of product is increasing.
In a chemical reaction, chemical equilibrium is the state in which both reactants and products are present in concentrations which not change with time.
Speed of direct and irreversible chemical reaction are equal
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Answer:
45.7kj
Explanation:
To calculates the heats of reaction from heats of formation:
∆Hr=£∆Hp -£∆Hr
= £∆Hch3ChOH - £∆HCh2h2+h20
=(-235.1kj)-(+52.47kj/kg + (-241.8kj/kg)
∆H = 45.71kj/kg
Answer:
Sodium hydroxide and water will react at room temperature. What does this indicate about its activation energy? The activation energy is at exactly 600 kJ. C. The activation energy is very low.
Explanation: