Its C.
Negative x Negative is positive, so its not A or D.
Positive x Positive is Positive, so its not B either.
C is your option because Positive x Negative is Negative, and vice verca.
Answer:
a) 0.778
b) 0.9222
c) 0.6826
d) 0.3174
e) 2 drivers
Step-by-step explanation:
Given:
Sample size, n = 5
P = 40% = 0.4
a) Probability that none of the drivers shows evidence of intoxication.



b) Probability that at least one of the drivers shows evidence of intoxication would be:
P(X ≥ 1) = 1 - P(X < 1)
c) The probability that at most two of the drivers show evidence of intoxication.
P(x≤2) = P(X = 0) + P(X = 1) + P(X = 2)
d) Probability that more than two of the drivers show evidence of intoxication.
P(x>2) = 1 - P(X ≤ 2)
e) Expected number of intoxicated drivers.
To find this, use:
Sample size multiplied by sample proportion
n * p
= 5 * 0.40
= 2
Expected number of intoxicated drivers would be 2
The best way for him to check his answer would be to simply plug in the value found for x into the equation.
4(2) - 6 = 2
8 - 6 = 2
2 = 2
Answer:
Step-by-step explanation:
Given the simultaneous equation
3x+4y=15. Equation 1
3x-y=30. Equation 2
Using elimination method
Sutract equation 2 from 1
Then, will have
3x-3x+4y--y=15-50. -×-=+
4y+y=-15
5y=-15
Divide Both sides by 5
y=-15/5
y=-3
From equation 2
3x-y=30
3x--3=30
3x+3=30
3x=30-3
3x=27
Divide both side by 3
x=27/3
x=9
Then, x=9 and y=-3
Considering the definition of zeros of a function, the zeros of the quadratic function f(x) = x² + 4x +9 do not exist.
<h3>Zeros of a function</h3>
The points where a polynomial function crosses the axis of the independent term (x) represent the so-called zeros of the function.
In summary, the roots or zeros of the quadratic function are those values of x for which the expression is equal to 0. Graphically, the roots correspond to the abscissa of the points where the parabola intersects the x-axis.
In a quadratic function that has the form:
f(x)= ax² + bx + c
the zeros or roots are calculated by:

<h3>This case</h3>
The quadratic function is f(x) = x² + 4x +9
Being:
the zeros or roots are calculated as:



and



If the content of the root is negative, the root will have no solution within the set of real numbers. Then
has no solution.
Finally, the zeros of the quadratic function f(x) = x² + 4x +9 do not exist.
Learn more about the zeros of a quadratic function:
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