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3 years ago

PLEASE ANSWER ASAP :"( I need to submit the homework and i dont understand how to do the solution

Mathematics

1 answer:

Feliz [49]3 years ago

3 0

Answer:

x -2 -1 0 1

y -1 2 5 8

Step-by-step explanation:

y=3x+5

When x=-2

y=3(-2)+5

y=-6+5

y=-1

when x=-1

y=3(-1)+5

y=-3+5

y=2

whenx=0

y=3(0)+5

y=5

When x=1

y=3(1)+5

y=3+5

y=8

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3 years ago

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Step-by-step explanation:

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In the United States, 35% of households own a 4K television. Suppose we take a random sample of 150 households. (a) Describe the

sattari [20]

Answer:

(a) The distribution of the sample proportion is Normal distribution.

(b) The probability that in this sample of 150 households that more than 50% own a 4K television is 0.00012.

Step-by-step explanation:

We are given that in the United States, 35% of households own a 4K television.

Suppose we take a random sample of 150 households.

Let $\hat p$ = sample proportion of households who own a 4K television.

The z-score probability distribution for sample proportion is given by;

Z = $\frac{ \hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ~ N(0,1)

where, $\hat p$ = sample proportion

p = population proportion of households own a 4K television = 35%

n = sample of households = 150

(a) The distribution of the sample proportion is related to the Normal distribution.

(b) Probability that in this sample of 150 households more than 50% own a 4K television is given by = P( $\hat p$ > 0.50)

P( $\hat p$ > 0.50) = P( $\frac{ \hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ > $\frac{ 0.50-0.35}{\sqrt{\frac{0.50(1-0.50)}{150} } }$ ) = P(Z > 3.67) = 1 - P(Z $\leq$ 3.67)

= 1 - 0.99988 = 0.00012

Now, in the z table the P(Z $\leq$ x) or P(Z < x) is given. So, the above probability is calculated by looking at the value of x = 3.67 in the z table which has an area of 0.99988.

Therefore, probability that in this sample of 150 households more than 50% own a 4K television is 0.00012.

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3 years ago

A null hypothesis is that the mean nose lengths of men and women are the same. The alternative hypothesis is that men have a lon

algol [13]

Answer:

b. There is not enough evidence to say that the populations of men and women have different mean nose lengths.

See explanation below.

Step-by-step explanation:

Develop the null and alternative hypotheses for this study?

We need to conduct a hypothesis in order to check if the means for the two groups are different (men have longer mean nose length than women), the system of hypothesis would be:

Null hypothesis: $\mu_{men} \leq \mu_{women}$

Alternative hypothesis: $\mu_{men} > \mu_{women}$

Assuming that we know the population deviations for each group, for this case is better apply a z test to compare means, and the statistic is given by:

$z=\frac{\bar X_{men}-\bar X_{women}}{\sqrt{\frac{\sigma^2_{men}}{n_{men}}+\frac{\sigma^2_{women}}{n_{women}}}}$ (1)

z-test: Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other.

Let's assume that the calculated statistic is $z_{calc}$

Since is a right tailed test test the p value would be:

$p_v =P(Z>z_{calc})=0.225$

And we know that the p value is 0.225. If we select a significance level for example 0.05 or 0.1 we see that $p_v >\alpha$

And on this case we have enough evidence to FAIl to reject the null hypothesis that the means are equal. So then the best conclusion would be:

b. There is not enough evidence to say that the populations of men and women have different mean nose lengths.

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3 years ago