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3 years ago

11

A right triangle has side lengths 5, 12, and 13 as shown below. Use these lengths to find cos B, tanB, and sin B. (Plz I need he

lp)

1 answer:

n200080 [17]3 years ago

6 0

Answer:

5/13, 12/5, 12/13

Step-by-step explanation:

cos = adj/hyp

tan = opp/adj

sin = opp/hyp

hyp = 13

adj = 5

opp = 12

Plug in.

cos = 5/13

tan = 12/5

sin = 12/13

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Step-by-step explanation:

We have been given that point a is at (-2,4) and point c is at (4,7) .

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We will use section formula to solve our given problem.

When point P divides a segment internally in the ratio m:n, the coordinates of point P would be:

$[x=\frac{mx_2+nx_1}{m+n}, y=\frac{my_2+ny_1}{m+n}]$

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