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katen-ka-za [31]
3 years ago
14

Point J (-2,1) and point K (4,5) form line segment JK. For the point P that partitions JK in the ration 3:7, what is the y- coor

dinate of P?
Mathematics
2 answers:
Ainat [17]3 years ago
7 0
Y = 2.4 and the x = -0.3
amid [387]3 years ago
6 0

Answer:

2.2

Step-by-step explanation:

If  point P (Xp, Yp) divides a line segment from J (Xj, Yj) to K (Xk, Yk) in the ratio a:b, then the y-coordinate of P is

Yp = Yj + a/(a+b) * (Yk - Yj)

Here Yj = 1, Yk = 5, a = 3 and b = 7. Replacing

Yp = 1 + 3/(3+7) * (5 - 1)

Yp = 2.2

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Caleb strung a 12 foot rope from the bottom of one fence post to the top of another. He measured the angle of elevation of the r
OLEGan [10]
The answer for this question is b because the angle of elevation of the rope as 35°
5 0
3 years ago
Given b(x) = |x+4], what is b(-10)?<br> -10<br> -6<br> 8<br> 14
GREYUIT [131]

Answer:

b(-10) = 6

Step-by-step explanation:

Step 1: Define

b(x) = |x + 4|

b(-10) is x = -10

Step 2: Substitute and Evaluate

b(-10) = |-10 + 4|

b(-10) = |-6|

b(-10) = 6

8 0
3 years ago
Read 2 more answers
Which proportion can be used to show that the slope of JL is equal to the slope of MP
Ilya [14]

Answer:

See below and attached

Step-by-step explanation:

<u>As per the graph we have:</u>

  • Coordinates of JL are J(-7, 4), L(-4, 0)
  • Coordinates of MP are M(-10, 8), P(-1, -4)

<u>Slope formula is:</u>

  • m = (y₂ - y₁)/(x₂ - x₁)

<u>Slope of JL:</u>

  • (0 - 4)/(-4-(-7)) = - 4 / 3

<u>Slope of MP:</u>

  • (-4 -8)/(-1- (-10)) = -12 / 9 = - 4/3

5 0
3 years ago
Which expression is equivalent to (9x10z2)(x5y3)
MAVERICK [17]

Answer:

9x^15y^3z^2 is your answer

Step-by-step explanation:

8 0
3 years ago
$13,957 is invested, part at 7% and the rest at 6%. If the interest earned from the amount invested at 7% exceeds the interest e
ch4aika [34]

Answer:

The Amount invested at 7% interest is $12,855

The Amount invested at 6% interest = $1,102  

Step-by-step explanation:

Given as :

The Total money invested = $13,957

Let The money invested at 7% = p_1  = $A

And The money invested at 6% = p_2 = $13957 - $A

Let The interest earn at 7% = I_1

And The interest earn at 6% = I_2

I_1 -  I_2 = $833.73

Let The time period = 1 year

Now,<u> From Simple Interest method</u>

Simple Interest = \dfrac{\textrm principal\times \textrm rate\times \textrm time}{100}

Or,  I_1 = \dfrac{\textrm p_1\times \textrm 7\times \textrm 1}{100}

Or,  I_1 = \dfrac{\textrm A\times \textrm 7\times \textrm 1}{100}

And

I_2 = \dfrac{\textrm p_2\times \textrm 6\times \textrm 1}{100}

Or,  I_2 = \dfrac{\textrm (13,957 - A)\times \textrm 6\times \textrm 1}{100}

∵  I_1 -  I_2 = $833.73

So, \dfrac{\textrm A\times \textrm 7\times \textrm 1}{100} -  \dfrac{\textrm (13,957 - A)\times \textrm 6\times \textrm 1}{100} = $833.73

Or, 7 A - 6 (13,957 - A) = $833.73 × 100

Or, 7 A - $83,742 + 6 A = $83373

Or, 13 A = $83373 + $83742

Or, 13 A = $167,115

∴ A = \dfrac{167115}{13}

i.e A = $12,855

So, The Amount invested at 7% interest = A = $12,855

And The Amount invested at 6% interest = ($13,957 - A) = $13,957 - $12,855

I.e The Amount invested at 6% interest = $1,102

Hence,The Amount invested at 7% interest is $12,855

And The Amount invested at 6% interest = $1,102   . Answer

8 0
3 years ago
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