Recall that 
and 
for all 
. So
For 
, we expect both 
and 
(i.e. the sine and cosine of any angle that lies in the first quadrant must be positive). By definition of absolute value, 
if 
.
So we have
making H the answer.
C is always true, because the inequality reduces to x > y.
Can you please show us the graph ?
y-intercept: Let x = 0 and solve for y:
(x-1)^2 + (y-2)^2 = 10 => (-1)^2 + y^2 - 4y + 4) = 10
=> 1 + y^2 - 4y + 4 = 10, or y^2 - 4y -5 = 0
The solutions of this quadratic are y = 5 and y = -1.
Thus, the y-intercepts are (0, 5) and (0, -1).
Now find the x-intercepts: Let y = 0 and solve the resulting equation for x:
(x-1)^2 = 10 - (-2)^2, or (x-1)^2 = 10 - 4 = 6.
Taking the sqrt of both sides, x - 1 = plus or minus sqrt(6), or:
x = 1 +√6 and x = 1 - √6, so that the x-intercepts
are (1+√6, 0) and (1-√6, 0).
I don't understand it. Explain more.
Step-by-step explanation:
Answer in attached image...
hope it helps
