Answer:
5.3
Step-by-step explanation:
Answer: Yes
Step-by-step explanation:
We will assume that each bulb is of 100 kW (kilowatt).
We will calculate how much energy in kilowatt-hours the light bulb will use per year in kilowatts, by the number of hours in a year.
We have, 100 kW = 0.1 kW so the energy consumed in one year is,
0.1 \times 8760=876.0\text {kWh} Since there are 8760 hours in one year. It is given that there are 9 bulbs so we need to have, 876 \times 9 = 7884 \text {kWh}
It is given that 1 ton of coal produces 2460 kWh, so 4 tons of coal will produce, 4\times 2460= 9840 \text {kWh}
We can observe that 4 tons of coal is producing 9840 kWh which is mroe than 7884 kWh. So, yes, 4 tons of coal can produce enough power to light 9 bulbs for a year
Given mass=1 kg, volume=400cm³, density=?
The formula for finding density is ρ=m/v where ρ is density, m is volume and vis volume
ρ=1kg/400cm³
ρ=0.0025kg/cm³
Therefore the density of the sand is 0.0025kg/cm³
9024152 Would be your answer!
Answer:
the first one
Step-by-step explanation:
the 4x's cancel out and 8 does not equal -14 so...