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Klio2033 [76]
3 years ago
5

Answer m/40 + 50 = 51

Mathematics
1 answer:
dexar [7]3 years ago
5 0

Answer:

m=40

Step-by-step explanation:

First you would subtract 50 from both sides to get -> m/40=1. So finally if you want to multiply 40 to both sides it would be m=40. Hope this helps!

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What is the sum of the last four terms of the series 7+9+11+...21
Sidana [21]

For sake of convenience, reverse the series, then it would be:

21,19,17.....7

a=21, d = -2,

s(4) = 4/2 (21+15)

s(4)=2(36)

s(4) = 72


8 0
3 years ago
A large pool of adults earning their first driver’s license includes 50% low-risk drivers, 30% moderate-risk drivers, and 20% hi
Mamont248 [21]

Answer:

The probability that these four will contain at least two more high-risk drivers than low-risk drivers is 0.0488.

Step-by-step explanation:

Denote the different kinds of drivers as follows:

L = low-risk drivers

M = moderate-risk drivers

H = high-risk drivers

The information provided is:

P (L) = 0.50

P (M) = 0.30

P (H) = 0.20

Now, it given that the insurance company writes four new policies for adults earning their first driver’s license.

The combination of 4 new drivers that satisfy the condition that there are at least two more high-risk drivers than low-risk drivers is:

S = {HHHH, HHHL, HHHM, HHMM}

Compute the probability of the combination {HHHH} as follows:

P (HHHH) = [P (H)]⁴

                = [0.20]⁴

                = 0.0016

Compute the probability of the combination {HHHL} as follows:

P (HHHL) = {4\choose 1} × [P (H)]³ × P (L)

               = 4 × (0.20)³ × 0.50

               = 0.016

Compute the probability of the combination {HHHM} as follows:

P (HHHL) = {4\choose 1} × [P (H)]³ × P (M)

               = 4 × (0.20)³ × 0.30

               = 0.0096

Compute the probability of the combination {HHMM} as follows:

P (HHMM) = {4\choose 2} × [P (H)]² × [P (M)]²

                 = 6 × (0.20)² × (0.30)²

                 = 0.0216

Then the probability that these four will contain at least two more high-risk drivers than low-risk drivers is:

P (at least two more H than L) = P (HHHH) + P (HHHL) + P (HHHM)

                                                            + P (HHMM)

                                                  = 0.0016 + 0.016 + 0.0096 + 0.0216

                                                  = 0.0488

Thus, the probability that these four will contain at least two more high-risk drivers than low-risk drivers is 0.0488.

6 0
3 years ago
If the m∠2 = 40, what is the m∠5?
77julia77 [94]

Answer: The answer is 100.

Step-by-step explanation: 40 divided by 2 = 20

x=20

20x5=100

5 0
3 years ago
Read 2 more answers
In ΔEFG, the measure of ∠G=90°, FG = 67 feet, and EF = 98 feet. Find the measure of ∠F to the nearest tenth of a degree.
Mama L [17]

Answer:

46.9 degrees is the answer

6 0
3 years ago
Find the z score that cuts-off the largest 9% under the standard normal curve. a) -1.34 b) 1.34 c) 0.536 d) 1.28
topjm [15]

Answer:

b) 1.34

Step-by-step explanation:

The z score is used to determine the number of standard deviations by which the raw score is above or below the mean. If the z score is positive then the z score is above the mean while for a negative z score implies that it is below the mean. The z score is given by:

z=\frac{x-\mu}{\sigma}

For the largest 9%, the score is 100% - 9% = 91% = 0.91

From the normal distribution table, the z score that corresponds to 0.91 is 1.34

4 0
3 years ago
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