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3 years ago

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Evaluate 5(14 – 23) + 8 ÷ 2. A. 26 B. 34 C. 44 D. 56

2 answers:

yKpoI14uk [10]3 years ago

5 0

Answer:

5(-9)+4

-45+4= -41

this is the answer

Keith_Richards [23]3 years ago

4 0

Answer:

We multiplu5(14-23)which will vive us 115-70 equivalent to -45 and then we divide 8÷2which will give us 4. Finally we add -45+4=-41

Step-by-step explanation:

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PLEASE HELP ASAP! What is the r-value of the following data, to three decimal places?

Kobotan [32]

A) Find the Sum of the X values: 4 +5+8+9+13 = 39

B) Find the Sum of the Y values: 23 +12 +10 +9 +2 = 56

C) Find the Sum of x^2: 4^2 + 5^2 + 8^2 + 9^2 +13^2 = 355

D) The sum of the Y^2's: 23^2 + 12^2 + 10^2 + 9^2 + 2^2 = 858

E) Sum of x *y's: 4*23 + 5*12 + 8*10 + 9*9 + 13*2 = 339

N = number of sets = 5

Numerator of r = (E - A*B/N) = 339-39*56/5 = 339 - 436.8 = -97.8

Denominator of r = SQRT(C-A^2/N) x SQRT(D-B^2/N) =
SQRT(355-39^2/5) x SQRT(858-56^2/5) =
SQRT(50.8) x SQRT(230.8) =
7.1274 x 15.1921 =
108.2803

r = -97.8 / 108.2803

r = -0.903

Answer is A

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4 years ago

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SVETLANKA909090 [29]

Answer:

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Step-by-step explanation:

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3 years ago

Some help will be nice, and I have some more questions to come!

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It would be 30 inches. Hopes this helps.

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3 years ago

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Alanna plants a tree that is 2 feet tall. The tree grows ¾ foot per year. Write a linear model that gives the height of the tree

ikadub [295]

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7 0

3 years ago

Find the dimensions of an open rectangular box with a square base that holds 2000 cubic cm and is constructed with the least bui

Vesnalui [34]

<h3>The dimensions of the given rectangular box are:</h3><h3>L = 15.874 cm , B = 15.874 cm , H = 7.8937 cm</h3>

Step-by-step explanation:

Let us assume that the dimension of the square base = S x S

Let us assume the height of the rectangular base = H

So, the total area of the open rectangular box

= Area of the base + 4 x ( Area of the adjacent faces)

= S x S + 4 ( S x H) = S² + 4 SH ..... (1)

Also, Area of the box = S x S x H = S²H

⇒ S²H = 2000

$\implies H = \frac{2000}{S^2}$

Substituting the value of H in (1), we get:

$A = S^2 + 4 SH = S^2 + 4 S(\frac{2000}{S^2}) = S^2 + (\frac{8000}{S})\\\implies A = S^2 + (\frac{8000}{S})$

Now, to minimize the area put :

$(\frac{dA}{dS} ) = 0 \implies 2S - \frac{8000}{S^2} = 0\\\implies S^3 = 4000\\\implies S = 15.874 \approx 16 cm$

Putting the value of S = 15.874 cm in the value of H , we get:

$\implies H = \frac{2000}{S^2} = \frac{2000}{(15.874)^2} = 7.8937 cm$

Hence, the dimensions of the given rectangular box are:

L = 15.874 cm

B = 15.874 cm

H = 7.8937 cm

3 0

4 years ago