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EleoNora [17]
3 years ago
6

Complete Eduardo's definition of parallel lines: "If two coplanar lines are both perpendicular to a third line in the same plane

, all of the angles formed between the two lines and the third line are "Explain your answer.​
Mathematics
1 answer:
vredina [299]3 years ago
4 0
Appendicular because science isn’t everything.
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If U = {all positive integers) and A = {x|x EU and x is an odd positive integer}, which describes AC?
Galina-37 [17]

Answer:

last choice

Step-by-step explanation:

If we are looking at positive integers and we take out the odd ones, the only one's that are left are the even ones.

So last choice.   (Also I assume AC meant the complement of A)

7 0
3 years ago
Read 2 more answers
Determine if the ordered pair (6, 4) is a solution to the inequality
Ugo [173]

Answer:

\Large \boxed{\mathrm{Option \ D}}

Step-by-step explanation:

(6, 4)

x = 6 and y = 4

y > -1/2x + 7

Plug in the values to check if it is true.

4 > -1/2(6) + 7

4 > -3 + 7

4 > 4

This statement is false.

(6, 4) lies on the line.

8 0
3 years ago
Can someone please help me as soon as possible!
Elena-2011 [213]
Ed = 96 but switch the numbers
6 0
3 years ago
Olivia is 48 inches tall, and 2/3 as tall as her brother Cameron. In inches, how tall is Cameron?
KengaRu [80]

Cameron is 72 inches tall.

48 x 3/2= 72 inches or 6 ft.

4 0
3 years ago
The height of a trapezoid is 8 in. And its area is 96 in2. One base of the trapezoid is 6 inches longer than the other base. Wha
Vsevolod [243]

Answer:

The lengths of the bases are 9 inches and 15 inches.

Step-by-step explanation:

The area of trapezoid is

=\frac12(\textrm{ sum of parallel sides})\times height

Given that the height of a trapezoid is 8 in. and its area is 96 in².

Assume the bases of the trapezoid be b₁ and b₂.

Since one base of the trapezoid 6 in. longer than the other.

Let, b₁=b₂+6

The area of the trapezoid is

=\frac 12 (b_1+b_2)\times8 in²

=\frac12 (b_2+6+b_2)\times 8 in²

=\frac12(2b_2+6)\times8 in²

According to the problem,

\frac12(2b_2+6)\times8 =96

\Rightarrow 2b_2+6=\frac{96\times 2}{8}                [ Multiplying \frac28 ]

\Rightarrow 2b_2+6=24

\Rightarrow 2b_2=24-6

\Rightarrow 2b_2=18

\Rightarrow b_2=\frac{18}{2}

\Rightarrow b_2=9

Then, b_1=b_2+6

              =9+6

             =15 in

The lengths of the bases are 9 inches and 15 inches.

5 0
3 years ago
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