The maximum number of roots to a polynomial of order n is n roots. Take the example of a quadratic (order 2) which can intersect the x-axis a maximum of 2 times, and similarly a cubic (order 3) 3 times maximum.
Hence for 8 intersections, minimum order = 8
3^5) (x + 2)^(3/2) + 3 = 27
<span>(x + 2)^(3/2) = 24 / 243 </span>
<span>x + 2 = [ 24 / 243 ]^(2/3) </span>
<span>x + 2 = [ 8 / 81 ]^(2/3) </span>
<span>x = [ 4 / 81^(2/3) ] - 2 =-1.786
the answer is x=-1.786</span>
The answer is the second option given
. . Hmmmmmmmmm, I wonder what the answer could be XD
Answer:106
Step-by-step explanation:
Let number of white marbles be w
Let number of red marbles be r
w+r = 126---------1
w = 6 +5r-----------2
Put eqn 2 in eqn 1
6+ 5r + r = 126
6 + 6r = 126
6r = 120
r = 20
w = 6 +5r =6+100
= 106
