All categories

3 years ago

Polygon ABCDE is reflected to produce polygon A’ B’ C’ D’ E’. What is the equation for the line of reflection?

Mathematics

1 answer:

Arisa [49]3 years ago

4 0

Answer:

B. x=0

Step-by-step explanation:

The Polygon ABCDE is reflected by

y-axis => x=0 , to produce polygon A’ B’ C’ D’ E’

You might be interested in

I need help asap please

Zigmanuir [339]

3/5 is smaller then 3/4(you can tell from denominators) 5/8 is smaller then 3/5, and 7/4 is greater then 1, so the only logical one is C. Hope this helped!

8 0

4 years ago

132 is 80% of what original price

sweet [91]

Answer:

660

Step-by-step explanation:

I multiplied 132 by 5 and then just to confirm I took 80% off of 660 and got 132 as my answer.

5 0

3 years ago

Find a polynomial of degree 3 with zeros of 4, 2i and -2i

andre [41]

$(x-4)(x-2i)(x+2i)=\\
(x-4)(x^2+4)=\\
x^3+4x-4x^2-16=\\
x^3-4x^2+4x-16$

7 0

3 years ago

What is y=1/2(x+3)^2+10 in standard form

anyanavicka [17]

Answer:

Simplified equation in standard form: $y=\frac{1}{4}x^{2}+12\frac{1}{4}$

Original equation in standard form: $y=1/2(x+3)^2+10$

Step-by-step explanation:

$y=\frac{1}{2}(x+3)^2+10$

Step 1: Distribute the $\frac{1}{2}$ :

$y=(\frac{1}{2}*x+\frac{1}{2}*3)^2+10$

$y=(\frac{1}{2}x+1\frac{1}{2})^2+10$

Step 2: Take $(\frac{1}{2}x+1\frac{1}{2})$ and square it :

$y=(\frac{1}{2}x+1\frac{1}{2})^2+10$

$y=(\frac{1}{2}x)^{2} +(1\frac{1}{2})^2+10$

$y=(\frac{1}{2}x*\frac{1}{2}x)+(1\frac{1}{2}*1\frac{1}{2})+10$

$y=\frac{1}{4}x^{2}+2\frac{1}{4}+10$

Step 3: Add the constants:

$y=\frac{1}{4}x^{2}+(2\frac{1}{4}+10)$

$y=\frac{1}{4}x^{2}+(12\frac{1}{4})$

Step 4: Get rid of the parenthesis:

$y=\frac{1}{4}x^{2}+12\frac{1}{4}$

3 0

3 years ago

Write 7.08 x 10 -4 in standard notation

MakcuM [25]

Answer:

it's 0.000708

Step-by-step explanation:

Thank you come again

4 0

3 years ago

Read 2 more answers