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Nata [24]
3 years ago
11

Joan has raised $306 by selling 34 equally priced boxes of chocolate for the team fund-raiser. Which of the following equations

can be used to find the price, n, of each box of chocolate?
n ÷ 34 = 306
34n = 306
n − 34 = 306
n + 34 = 306
Mathematics
2 answers:
dsp733 years ago
7 0
Answer 34n=306 hope this helps
Elza [17]3 years ago
5 0

Answer:

34n=306

Step-by-step explanation:

Use inverse operation to find it, 306÷34= 9, check again 34(9)=306, so it's correct!

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40w-16=8(5w-2)

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Answer:

B. 41.8° is the correct answer

Step-by-step explanation:

We are given that,

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Now, using the law of cosines, we get,

238^2=273^2+357^2-2\times 273\times 357\times \cos \theta

i.e. 56644=74529+127449-194922\times \cos \theta

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i.e. 194922\times \cos \theta=145334

i.e. \cos \theta=0.7456

i.e. \theta=\arccos 0.7456

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Which of these could be the dimensions of a unit cube? Select all that apply.
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c and e

Step-by-step explanation:

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Answer:

The height of the right trapezoid is   \frac{6}{5+\sqrt{3}}\ units

Step-by-step explanation:

Let

x ----> the height of the right trapezoid in units

we know that

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we have

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AB=BC=CH=HA=x ---> because is a square

substitute

6=x+x+CD+DH+x

6=3x+CD+DH -----> equation A

<em>In the right triangle CDH</em>

sin(30\°)=\frac{CH}{CD}

sin(30\°)=\frac{1}{2}

so

Remember  that CH=x

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tan(30\°)=\frac{\sqrt{3}}{3}

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\frac{\sqrt{3}}{3}=\frac{x}{DH}

DH=x\sqrt{3}

substitute the values in the equation A

6=3x+CD+DH -----> equation A

CD=2x

DH=x\sqrt{3}

6=3x+2x+x\sqrt{3}

6=5x+x\sqrt{3}

6=x[5+\sqrt{3}]

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