Answer: Ix+10I
Step-by-step explanation: To shift the graph 10 units to the left, we replace x with x+10. What's really going on is that the xy axis shifts 10 units to the right (because x is now x+10; eg, x = 2 ---> x+10 = 2+10 = 12) so it appears that the graph is moving to the left. The general rule is h(x) = g(x+10).
So,
g(x) = |x|
g(x+10) = |x+10| ... every x has been replaced with x+10
h(x) = g(x+10)
h(x) = |x+10|
We can use a graphing tool like GeoGebra to visually confirm we have the right answer (see attached). Note how a point like (0,0) on the green graph moves to (-10,0) on the red graph.
9514 1404 393
Answer:
a) BE = 5; DE = 6; EF = 4
b) ∠EFC ≅ ∠DA.F ≅ ∠BDE or <em>b = e = f = i</em>
Step-by-step explanation:
Each short segment is the same length as the marked one it is parallel to.
E is the midpoint of BC, so BE = EC = 5.
ADEF is a parallelogram, so DE = A.F = 6.
D is the midpoint of AB, so AD = DB = 4. ADEF is a parallelogram, so ...
EF = AD = 4
__
As we have noted, AB║EF and DE║A.F, so corresponding angles and alternate interior angles are congruent. <em>b = e = f = i</em>
Answer:
The graph with B(2,-3) i.e) y=
x goes through the point M(-10,15).
Step-by-step explanation:
Consider M(-10,15) and given that equation is y = kx.
Now, substitute M(-10,15) in the equation
⇒ 15 = k × -10
⇒ k = 
=
⇒ y = x
Now, check with the given points B(2,-3) and B(
, -2)
1) B(2,-3)
y = x
⇒(-3) = × 2
⇒ -3 = -3 ⇒ LHS = RHS
⇒ B(2,-3) is the required point.
2) for b( , -2)
LHS ≠ RHS.
So,The graph with B(2,-3) i.e) y= x goes through the point M(-10,15).
Answer:
If a is 1.. we substitute one in every a in g(a)
4 * 1 + 16
4+ 16 = 20
g(a)= 20
f(20)
-16 + 20 = 4
and 4/4 = 1
so f (g (a)) = a
Step-by-step explanation:
First you would do -30x5 which equals -150 then 2-150 equals -148
