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denis-greek [22]
3 years ago
9

A bag contains 5 yellow 6 red and 4 green marbles. 2 marbles are drawn the first is replaced before tue 2nd is drawn. A random v

ariable assigns the number of green marbles to each outcome Calculate the expected value of the random variable
Mathematics
1 answer:
levacccp [35]3 years ago
4 0
The correct answer is 53
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Repartir 310 nueces entre tres personas de modo que la segunda reciba 20 menos que la primera y 40 mas que la tercera
almond37 [142]

Answer:

2

Step-by-step explanation:

625282629283637hshshs

3 0
3 years ago
Solve the following problems:
liq [111]

Answer:

  • Q1. 42 liters
  • Q2. Php. 330  

Step-by-step explanation:

Question 1

<u>Use ratios to solve:</u>

  • 12/100 = x/350
  • x = 12*350/100
  • x = 42 liters

Question 2

  • 1 basket → 5 1/2 kg ⇒ 2 baskets → 2(5 1/2) = 11 kg
  • 1 kg → 30 ⇒ 11 kg → 11*30 =  330  

Mutya earned Php. 330  

4 0
3 years ago
Which equation is equivalent to StartRoot x squared + 81 EndRoot = x + 10?
marishachu [46]

The given equation is equivalent to Option D .

The mission option is

A. x+10= x+10

B. x+9 =x² + 20x + 100

C. x² +81 = x² + 100

D. x² + 81 = x² +20x + 100

<h3>What is an Equation ?</h3>

An equation is a mathematical statement formed when two algebraic expression is equated by an equal sign .

An equation is given in the question

\rm \sqrt{x^2 + 81} = x +10

\rm {x^2 + 9^2} = (x +10)^2

\rm {x^2 + 81} = x^2 +20x + 100

Therefore the given equation is equivalent to Option D .

To know more about Equation

brainly.com/question/10413253

#SPJ1

5 0
2 years ago
For a certain​ candy, 15​% of the pieces are​ yellow, 1010​% are​ red, 2020​% are​ blue, 55​% are​ green, and the rest are brown
MatroZZZ [7]
A) the probability it is brown would be 50%; the probability it is yellow or blue would be 35%; the probability it is not green is 95%; the probability it is striped is 0%.
B) the probability of all brown would be 12.5%; the probability that the third one is the first red one drawn is 8.1%; the probability that none are yellow is 61.4%; the probability that at least one is green is 14.3%.

Explanation:
A) The probability that it is brown is the percentage of brown we have.  Brown is not listed, so we subtract what we are given from 100%:
100-(15+10+20+5) = 100-(50) = 50%.  The probability that one drawn is yellow or blue would be the two percentages added together:  15+20 = 35%.  The probability that it is not green would be the percentage of green subtracted from 100:  100-5=95%.  Since there are no striped candies listed, the probability is 0%.
B) Since we have an infinite supply of candy, we will treat these as independent events.  All 3 being brown is found by taking the probability that one is brown and multiplying it 3 times:
0.5*0.5*0.5 = 0.125 = 12.5%.  
To find the probability that the first one that is red is the third one drawn, we take the probability that it is NOT red, 100-10 = 90% = 0.9, for the first two, and the probability that it IS red, 10% = 0.1, for the last:
0.9*0.9*0.1 = 0.081 = 8.1%.

The probability that none are yellow is found by raising the probability that the first one is not yellow, 100-15=85%=0.85, to the third power:

0.85^3 = 0.614 = 61.4%.

The probability that at least one is green is computed by subtracting 1-(probability of no green).  We first find the probability that all three are NOT green:
0.95^3 = 0.857375
1-0.857375 = 0.143 = 14.3%.
3 0
3 years ago
-3x minus 2 minus -6x = -4 minus -4x plus 12
DochEvi [55]

-3x-2-6x=-4-<em>(-4x)</em>+12

-9x-2=-16x+12

7x=14

x=2.

You probably got confused with the italicized part.

6 0
3 years ago
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