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2 years ago

In 2013 number of students in a small school is 284.it is estimated that student population will increase by 4 percent

1 answer:

5 0

The situation can be modeled by a geometric sequence with an initial term of 284. The student population will be 104% of the prior year, so the common ratio is 1.04.

Let \displaystyle PP be the student population and \displaystyle nn be the number of years after 2013. Using the explicit formula for a geometric sequence we get

{P}_{n} =284\cdot {1.04}^{n}P

=284⋅1.04

We can find the number of years since 2013 by subtracting.

\displaystyle 2020 - 2013=72020−2013=7

We are looking for the population after 7 years. We can substitute 7 for \displaystyle nn to estimate the population in 2020.

\displaystyle {P}_{7}=284\cdot {1.04}^{7}\approx 374P

=284⋅1.04

≈374

The student population will be about 374 in 2020.

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3 years ago

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Korolek [52]

Answer:

1.08T/ (1+8/100)T

Step-by-step explanation:

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3 years ago

a meat pie contains chicken and turkey in the ratio 4:1. The pie contains 200g of Chicken. How much turkey is in the pie?

kogti [31]

Answer:

50 grams

Step-by-step explanation:

From the above question:

Chicken : Turkey

= 4:1

Sum Proportions = 4 + 1 = 5

We have to find the weight in grams of the entire pie

Let us represent the weight in grams of the entire pie = x.

The pie contains 200g of Chicken.

Hence:

4/5 × x = 200g

4x/5 = 200g

Cross Multiply

4x = 200g × 5

x = 200g × 5/4

x = 250g

The amount turkey that is in the pie is calculated as:

Total weight of pie - Amount of Chicken in the pie

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2 years ago

Find the savings plan balance after 2 years with an APR of 4% and monthly payments of $250. The balance is $ (Do not round until

alexdok [17]

Answer:

$6,506.51

Step-by-step explanation:

Recall that increasing an amount C in x% is equivalent to multiply it by (1+x/100)

As we have 4% APR, the monthly interest would be (4/12)% = 0.04/12

Month 0 (first payment)

$250

Month 1

$250 + 250 \frac{0.04}{12}= 250(\frac{12.04}{12})$

Month 2

$250(1+\frac{12.04}{12}+(\frac{12.04}{12})^2)$

Month 3

$250(1+\frac{12.04}{12}+(\frac{12.04}{12})^2+(\frac{12.04}{12})^3)$

Month 24 (2 years)

$250(1+\frac{12.04}{12}+(\frac{12.04}{12})^2+(\frac{12.04}{12})^3+...+(\frac{12.04}{12})^{24})$

The sum

$1+\frac{12.04}{12}+(\frac{12.04}{12})^2+(\frac{12.04}{12})^3+...+(\frac{12.04}{12})^{24}$

is the sum of the first 24 terms of a geometric sequence with common ratio $\frac{12.04}{12}$ which is

$\frac{1-(12.04/12)^{25}}{1-(12.04/12)}=26.02603071$

so, after 2 years the saving balance is

250*26.02603071 = 6,506.50767= $6,506.51 rounded to the nearest cent.

6 0

3 years ago