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3 years ago

What is the equation of a line in slope intercept form that passes through (-2,2) and is perpendicular to the graph of y=1/2x-3.

1 answer:

6 0

The answer is y = -2x-2

To find the slope of a line perpendicular to your equation, you just need to find the reciprocal. This just means flip the signs (change positive to negative, or negative to positive) and flip the numerator and denominator. So if you have 1/4 as your slope, the perpendicular slope would be -4/1 (which is just negative 4).

I changed the “b” from -3 to -2 so it would run through the points (-2, 2).

I hope this helps :)

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Na którym rysunku narysowano symetralną odcinka KL?<br>Która z tych liter nie ma osii symetrii?

tensa zangetsu [6.8K]

Answer:

- Only Drawing D has KL being a symmetrical segment.

- Drawings A, B and C have no axis of symmetry.

- Tylko rysunek D ma KL będący segmentem symetrycznym.

- Rysunki A, B i C nie mają osi symetrii.

Step-by-step explanation:

English Translation

In which drawing was the symmetrical segment of KL drawn? Which of these letters has no axis of symmetry?

Solution

The attached image to the question is presented in the attached image to this Solution.

Symmetry is a concept where a figure/shape has half of its part being a mirror image of the other part.

About the line or axis of symmetry, the structure or figure can be rotated at right angles or whole number multiples of right angles and the resulting structure is still the same as the one we started with.

Of the 4 drawings, only drawing D satisfies this conditions/criteria. And Hence, it is the only drawing amongst the four with an axis of symmetry.

In Polish/Po polsku

Załączony obraz do pytania jest przedstawiony na załączonym obrazku do tego rozwiązania.

Symetria to koncepcja, w której figura / kształt ma połowę swojej części stanowiącą odbicie lustrzane drugiej części.

W odniesieniu do linii lub osi symetrii, strukturę lub figurę można obracać pod kątem prostym lub wielokrotności liczby całkowitej pod kątem prostym, a wynikowa struktura jest nadal taka sama jak ta, od której zaczęliśmy.

Z 4 rysunków tylko rysunek D spełnia te warunki / kryteria. I dlatego jest to jedyny rysunek wśród czterech z osią symetrii.

Hope this Helps!!!

Mam nadzieję że to pomoże!!!

3 0

3 years ago

What is the fraction for 0.2

Olenka [21]

1/5 this is the closest answer i can think of

3 0

3 years ago

Read 2 more answers

The ratio of passenger cars to cargo cars in

gayaneshka [121]

Answer:

126

Step-by-step explanation:

the number of cargo cars is represented by the 35 part of the ratio , then

105 ÷ 35 = 3 ← value of 1 part of the ratio , then

passenger cars = 7 × 3 = 21

total cars = 105 + 21 = 126

4 0

2 years ago

Simplify 2(x + y) + 3(x + y)

ANTONII [103]

The answer would be 5x+5y

5 0

3 years ago

Find the critical numbers of the function f(x) = x6(x − 1)5 what does the first derivative test tell you that the second derivat

patriot [66]

The given function is f(x) = x⁶(x-1)⁵

The first derivative is
f'(x) = 6x⁵(x-1)⁵ + 5x⁶(x-1)⁴
= x⁵(x-1)⁴(6x - 6 + 5x)
= x⁵(x-1)⁴(11x - 6)
The critical values are the zeros of f'(x). They are
x = 0, 6/11, and 1.
The critical values indicate that turning points exist for f(x) at the critical points. However, we do not know the nature of the turning points.

Write the first derivative in the form f'(x) = (x-1)⁴(11x⁶ - 6x⁵).
The second derivative is
f''(x) = 4(x-1)³(11x⁶ - 6x⁵) + (x-1)⁴(66x⁵ - 30x⁴)
= (x-1)³(44x⁶ - 24x⁵ + 66x⁶ - 30x⁵ - 66x⁵ + 30x⁴)
= (x-1)³(110x⁶ - 120x⁵ + 30x⁴)
= 10x⁴(x-1)³(11x² - 12x + 3)
The sign of f''(x) at the critical values tell us the nature of the turning point.

f''(0) = 0, therefore a point of inflection exists at x = 0.
f''(6/11) > 0, therefore a local minumum exists at x = 6/11.
f''(1) = 0, therefore a point of inflection exists at x=1.

The graphs shown below confirm these results.

8 0

3 years ago