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Yuri [45]
3 years ago
6

Can someone help thanks.

Mathematics
2 answers:
docker41 [41]3 years ago
8 0

Answer:

= { \sf{ \frac{1}{ 144 } }}

Step-by-step explanation:

= { \tt{ \frac{1}{ {12}^{2} } }} =  \frac{1}{144}

Vitek1552 [10]3 years ago
7 0

Answer:

1/144

Step-by-step explanation: I presume..

And recall something from Algebra...

I hope it helps...

Square it

And reverse it because of the negative

It is a fraction

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300 sq units. hope it will help you!

Step-by-step explanation:

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Someone please help!!!!!!
Kaylis [27]
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3 years ago
-1/2x + 1/8 = -1/3x - i/4
brilliants [131]

Answer:

x= 4/9

Step-by-step explanation:

-1/(2x) + 1/8 = -1/(3x) - 1/4

-1/(2x)+1(3x)= - 1/4 -1/8

-3/(6x)+2(6x) = -2/8 -1/8

- 1/(6x) = - 3/8

-1*8 = -3*6x

8=18x

x= 8/18= 4/9

Check:

-1/(2*4/9) + 1/8 = -1/(3*4/9) - 1/4

- 1(8/9) + 1/8 = - 1/(4/3)-1/4

-9/8+1/8 = - 3/4-1/4

-1 = -1

3 0
3 years ago
Let w(s,t)=f(u(s,t),v(s,t)) where u(1,0)=−6,∂u∂s(1,0)=5,∂u∂1(1,0)=7 v(1,0)=−8,∂v∂s(1,0)=−8,∂v∂t(1,0)=6 ∂f∂u(−6,−8)=−1,∂f∂v(−6,−8
Blababa [14]
w(s,t)=f(u(s,t),v(s,t))

From the given set of conditions, it's likely that you are asked to find the values of \dfrac{\partial w}{\partial s} and \dfrac{\partial w}{\partial t} at the point (s,t)=(1,0).

By the chain rule, the partial derivative with respect to s is

\dfrac{\partial w}{\partial s}=\dfrac{\partial f}{\partial u}\dfrac{\partial u}{\partial s}+\dfrac{\partial f}{\partial v}\dfrac{\partial v}{\partial s}

and so at the point (1,0), we have

\dfrac{\partial w}{\partial s}\bigg|_{(s,t)=(1,0)}=\dfrac{\partial f}{\partial 
u}\bigg|_{(u,v)=(-6,-8)}\dfrac{\partial u}{\partial s}\bigg|_{(s,t)=(1,0)}+\dfrac{\partial f}{\partial 
v}\bigg|_{(u,v)=(-6,-8)}\dfrac{\partial v}{\partial s}\bigg|_{(s,t)=(1,0)}
\dfrac{\partial w}{\partial s}\bigg|_{(s,t)=(1,0)}=(-1)(5)+(2)(-8)=-21

Similarly, the partial derivative with respect to t would be found via

\dfrac{\partial w}{\partial t}\bigg|_{(s,t)=(1,0)}=\dfrac{\partial f}{\partial 
u}\bigg|_{(u,v)=(-6,-8)}\dfrac{\partial u}{\partial t}\bigg|_{(s,t)=(1,0)}+\dfrac{\partial f}{\partial 
v}\bigg|_{(u,v)=(-6,-8)}\dfrac{\partial v}{\partial t}\bigg|_{(s,t)=(1,0)}
\dfrac{\partial w}{\partial t}\bigg|_{(s,t)=(1,0)}=(-1)(7)+(2)(6)=5
6 0
4 years ago
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