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Stella [2.4K]
3 years ago
15

the amount of money rqised at a charity fundraiser varies directly with the number of attendees. the amount of money raised by 1

4 attendees was $231. how much money will be raised if there 45 attendees?
Mathematics
1 answer:
ss7ja [257]3 years ago
6 0
The raised 742.5 for 45 attendees
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Anna007 [38]

Answer:

A. Dilation of scale factor 2

B. Reflection over the y-axis

C. Reflection over the line y=x

D. Translation 1 unit left and 1 unit up

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PLZZZ HELPPPP Assume line q is parallel to line m. Choose from the drop-down menus to solve for m∠6​​
Vikentia [17]

Answer:

1= 75 2= 60 3=180 4=45 5= vertical angles 6=45

Step-by-step explanation:

All we have to do is use supplimentary angles

For example angle 1

105+angle 1=180

angle one = 75 degrees

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So angle 1 + angle 2+ angle 7= 180

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2 years ago
Write a third degree polynomial function that has real zeros -1, -2 and 4
ra1l [238]

Answer:

f(x) = x^{3}  - x^{2}  -  10x  -8

Step-by-step explanation:

All you have to do is multiply (x + 1)(x + 2)(x - 4)

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So,  f(x) = x^{3}  - x^{2}  -  10x  -8

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100-99+98-97+96-95...2-1=
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3 years ago
Drag the expressions into the boxes to correctly complete the table.
lora16 [44]

Answer:

SUMMARY:

x^4+\frac{5}{x^3}-\sqrt{x}+8                               →    Not a Polynomial

-x^5+7x-\frac{1}{2}x^2+9                           →    A Polynomial

x^4+x^3\sqrt{7}+2x^2-\frac{\sqrt{3}}{2}x+\pi              →    A Polynomial

\left|x\right|^2+4\sqrt{x}-2                                   →    Not a Polynomial

x^3-4x-3                                        →    A Polynomial

\frac{4}{x^2-4x+3}                                              →    Not a Polynomial

Step-by-step explanation:

The algebraic expressions are said to be the polynomials in one variable which consist of terms in the form ax^n.

Here:

n = non-negative integer

a = is a real number (also the the coefficient of the term).

Lets check whether the Algebraic Expression are polynomials or not.

Given the expression

x^4+\frac{5}{x^3}-\sqrt{x}+8

If an algebraic expression contains a radical in it then it isn’t a polynomial. In the given algebraic expression contains \sqrt{x}, so it is not a polynomial.

Also it contains the term \frac{5}{x^3} which can be written as 5x^{-3}, meaning this algebraic expression really has a negative exponent in it which is not allowed. Therefore, the expression x^4+\frac{5}{x^3}-\sqrt{x}+8 is not a polynomial.

Given the expression

-x^5+7x-\frac{1}{2}x^2+9

This algebraic expression is a polynomial. The degree of a polynomial in one variable is considered to be the largest power in the polynomial. Therefore, the algebraic expression is a polynomial is a polynomial with degree 5.

Given the expression

x^4+x^3\sqrt{7}+2x^2-\frac{\sqrt{3}}{2}x+\pi

in a polynomial with a degree 4. Notice, the coefficient of the term can be in radical. No issue!

Given the expression

\left|x\right|^2+4\sqrt{x}-2

is not a polynomial because algebraic expression contains a radical in it.

Given the expression

x^3-4x-3

a polynomial with a degree 3. As it does not violate any condition as mentioned above.

Given the expression

\frac{4}{x^2-4x+3}

\mathrm{Apply\:exponent\:rule}:\quad \:a^{-b}=\frac{1}{a^b}

Therefore, is not a polynomial because algebraic expression really has a negative exponent in it which is not allowed.

SUMMARY:

x^4+\frac{5}{x^3}-\sqrt{x}+8                               →    Not a Polynomial

-x^5+7x-\frac{1}{2}x^2+9                           →    A Polynomial

x^4+x^3\sqrt{7}+2x^2-\frac{\sqrt{3}}{2}x+\pi              →    A Polynomial

\left|x\right|^2+4\sqrt{x}-2                                   →    Not a Polynomial

x^3-4x-3                                        →    A Polynomial

\frac{4}{x^2-4x+3}                                              →    Not a Polynomial

3 0
3 years ago
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