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V125BC [204]
3 years ago
11

Can someone figure this out for me?

Mathematics
1 answer:
Digiron [165]3 years ago
7 0

Answer:

44°

Step-by-step explanation:

cos B = 0.7193  =  44°

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Write the answer to 6 2/5 × 4 in improper fraction form AND mixed number form.
Leni [432]

Answer:

6 2/5 as an improper fraction is 32/5 and if we turn 4 into a fraction (4/1) we can multiply them.

32/5 * 4/1 = 128/5

128/5 is the improper fraction

and the mixed number is 25 3/5

Step-by-step explanation:

6 2/5 as an improper fraction is 32/5 and if we turn 4 into a fraction (4/1) we can multiply them.

32/5 * 4/1 = 128/5

6 0
3 years ago
How can I solve? m(m-1)=812
Ymorist [56]
M^2+-m=812
this is the final answer

8 0
4 years ago
As an estimation we are told 5 miles is 8 km. <br> Convert 92 km to miles.
AlekseyPX

Answer:

105 miles

Step-by-step explanation:

3 0
3 years ago
The numbers 5, 6, 7, and 8 are randomly arranged to create a four-digit number. What is the probability that the number formed i
myrzilka [38]

Using the <u>arrangements and the probability concept</u>, it is found that there is a 0.75 = 75% probability that the number formed is not divisible by 4.

  • A probability is the <u>number of desired outcomes divided by the number of total outcomes</u>.
  • The number of possible arrangements of n elements is given by A_n = n!

In this problem, there are 4 elements, hence n = 4, T = A_4 = 4! = 24.

A number is a multiple of 4 if the <u>number composed by it's last 2 digits are multiples of 4</u>.

  • Hence, the possible options for the last 2 digits are: 56, 68, 76.
  • For each of them, there are A_2 = 2! = 2 options for the first 2 digits, hence, there will be 2 x 3 = 6 multiples of 4.

The other 18 numbers formed are not divisible by 4, hence:

p = \frac{18}{24} = 0.75

0.75 = 75% probability that the number formed is not divisible by 4.

For more on <u>arrangements and probabilities</u>, you can check brainly.com/question/24437717

5 0
2 years ago
Max has 2/1/4 of milk in her refrigerator. She likes to have
UkoKoshka [18]
yes? what is the question
7 0
4 years ago
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