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andreyandreev [35.5K]
3 years ago
6

What is the volume of the rectangular pyramid shown belown?

Mathematics
1 answer:
Anna35 [415]3 years ago
7 0

9514 1404 393

Answer:

  168 cubic inches

Step-by-step explanation:

The formula for the volume of a pyramid is ...

  V = (1/3)Bh

where B is the area of the base, and h is the height.

The base is a rectangle, whose are is given by the formula ...

  A = LW

  A = (8 in)(7 in) = 56 in²

Then the pyramid volume is ...

  V = (1/3)(56 in²)(9 in) = 168 in³

The volume of the pyramid is 168 cubic inches.

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guajiro [1.7K]

Answer:

x < 6

Step-by-step explanation:

5x < 30

5x/5 < 30/5

x < 6

5 0
3 years ago
Read 2 more answers
Solve the following quadratic function<br> by utilizing the square root method.<br> y = 100 – x2
Anna [14]

Answer:

x = ± 10

Step-by-step explanation:

To solve the equation let y = 0 , that is

0 = 100 - x²( add x² to both sides )

x² = 100 (I take the square root of both sides )

x = ± \sqrt{100} = ± 10

Then solution is x = - 10, x = 10

3 0
3 years ago
Suppose you want to find the difference of two sinusoidal currents, given as follows: i1(t)=I1 cos(ωt+ϕ1) and i2(t)=I2 cos(ωt+ϕ2
viktelen [127]

Answer:

  120.51·cos(377t+4.80°)

Step-by-step explanation:

We can use the identity ...

  sin(x) = cos(x -90°)

to transform the second waveform to ...

  i₂(t) = 150cos(377t +50°)

Then ...

  i(t) = i₁(t) -i₂(t) = 250cos(377t+30°) -150cos(377t+50°)

A suitable calculator finds the difference easily (see attached). It is approximately ...

  i(t) = 120.51cos(377t+4.80°)

_____

The graph in the second attachment shows i(t) as calculated directly from the given sine/cosine functions (green) and using the result shown above (purple dotted). The two waveforms are identical.

8 0
4 years ago
I need an answer asap if you know thanks it is worth a lot of points your welcome
Snowcat [4.5K]
A. multiplication is your answer.
6 0
3 years ago
Read 2 more answers
A student was asked to find a 90% confidence interval for the proportion of students who take notes using data from a random sam
Scorpion4ik [409]

Answer:

After use the formula we got the following result for the 90% confidence interval (0.13 <p<0.34)

And the conclusion for this case would be:

e. With 90% confidence, the proportion of all students who take notes is between 0.13 and 0.34.

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

Description in words of the parameter p

p represent the real population proportion of students who take notes

\hat p represent the estimated proportion of students who take notes

n is the sample size required  

z_{\alpha/2} represent the critical value for the margin of error  

The population proportion have the following distribution  

p \sim N(p,\sqrt{\frac{p(1-p)}{n}})

Numerical estimate for p

In order to estimate a proportion we use this formula:

\hat p =\frac{X}{n} where X represent the number of people with a characteristic and n the total sample size selected.

Confidence interval

The confidence interval for a proportion is given by this formula  

\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}  

For the 90% confidence interval the value of \alpha=1-0.90=0.1 and \alpha/2=0.05, with that value we can find the quantile required for the interval in the normal standard distribution.  

z_{\alpha/2}=1.64  

After use the formula we got the following result for the 90% confidence interval (0.13 <p<0.34)

And the conclusion for this case would be:

e. With 90% confidence, the proportion of all students who take notes is between 0.13 and 0.34.

6 0
3 years ago
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