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meriva
3 years ago
10

Find the value of x in the isosceles triangle

Mathematics
2 answers:
zimovet [89]3 years ago
8 0

That is a question about triangles.

In my answer I will show 2 ways to solve that question, ok? Let's go.

<h3>First way - Pythagoras's theorem</h3>

The line segment <em>x</em> divide the biggest triangle in 2 equals right triangles.

Let's choose one of them and note that is a triangule with hypotenuse equals to 8 and one cathetus equals to half of 8.

The Pythagoras's theorem says that:

\boxed{a^2 = b^2 + c^2}

<em>a </em>is the hypotenuse and <em>b</em> and <em>c </em>are cathetus.

So, in our case, we know the hypotenuse and one cathetus, let's substitute that in the expression:

a^2 = b^2 + c^2\\8^2 = 4^4 + c^2\\64 = 16 + c^2\\c^2 = 64 - 16\\c^2 = 64 -16\\c^2 = 48\\c = \sqrt{48}\\c= 4\sqrt{3}

Therefore, the value of x is 4\sqrt{3}.

<h3>Second way - The equilateral triangle height</h3>

That way to solve the question is a consequence of the previous way.

That triangle has all the sides equals, so it is a equilateral triangle.The line segment <em>x </em>is the height of that triangle. And we can find the equilateral triangle height using that expression:

\boxed{h = \frac{S\cdot \sqrt{3} }{2} }

<em>h </em>is the height and <em>S </em>is the triangle's side.

So, we know that the side of our triangle is 8. Let's change S value in the expression:

h = \frac{S\cdot \sqrt{3} }{2} \\h = \frac{8\cdot \sqrt{3} }{3} \\h = 4\sqrt{3}

Thus, the value of <em>x </em>is 4\sqrt{3}.

Note that in the 2 ways we find the same result, so that answer is correct.

I hope I've helped. :D

Enjoy your studies! \o/

SCORPION-xisa [38]3 years ago
4 0

Step-by-step explanation:

Since all 3 sides of the triangle is equal, it is not only an isosceles, but an equilateral triangle.

x = 8sin60° = 6.928 or sqrt48.

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