Answer:
x=2.125
y=0
C=19.125
Step-by-step explanation:
To solve this problem we can use a graphical method, we start first noticing the restrictions
and
, which restricts the solution to be in the positive quadrant. Then we plot the first restriction
shown in purple, then we can plot the second one
shown in the second plot in green.
The intersection of all three restrictions is plotted in white on the third plot. The intersection points are also marked.
So restrictions intersect on (0,0), (0,1.7) and (2.215,0). Replacing these coordinates on the objective function we get C=0, C=11.9, and C=19.125 respectively. So The function is maximized at (2.215,0) with C=19.125.
Answer:
i have
Step-by-step explanation:
if those are fractions being five and two thirds etc... I believe it would be 17/6. if you convert to improper fractions and then get a common denominator to subtract that should do it. Hope that helps.
The answer is X-2 ........
I just took the test the correct answer is:
Amplitude = 3 feet; 3 period = 16 hours; midline: y = 5.