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olga55 [171]
3 years ago
5

Simplify 4r-4r-10s+2s

Mathematics
1 answer:
sertanlavr [38]3 years ago
5 0

The answer is: −8s

Hope this helps :)

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The equation of a circle is ( x - 3) 2 + ( y + 2) 2 = 25. The point (8, -2) is on the circle.
Shtirlitz [24]

Answer:

x =8 is the equation of the tangent.

Step-by-step explanation:

Here the equation of the given circle is: (x-3)^{2}  + (y+2)^{2}  = 25

Now, comparing it with the general equation of circle: (x-h)^{2}  + (y -k)^{2}  = r^2

we get the central coordinates (h,k)  = (3,-2)

So, the slope of the line joining center and (8, -2) = \frac{-2 -(-2)}{8-3} = \frac{0}{5} = 0

Since the slope of line = 0, line is parallel to x axis.

Now, as tangent and the line is perpendicular to each other

⇒Slope of the tangent = -1/ slope of the line = \frac{-1}{0}

Now, by point slope formula: the equation of the tangent is

(y-y0)  = m (x-x0)

or, (y +2) = \frac{-1}{0} (x -8)

or x =8 is the equation of the tangent.

8 0
3 years ago
Two planes, which are 2235 miles apart, fly toward each other. Their speeds differ by 95 mph. If they pass each other in 3 hours
lora16 [44]

Answer:

325 mph and 420 mph

Step-by-step explanation:

If the speed of the slower plane is x, then the speed of the faster plane is x + 95.

The distance traveled by the slower plane is 3x.

The distance traveled by the faster plane is 3(x + 95).

The total distance is 2235 miles.

3x + 3(x + 95) = 2235

3x + 3x + 285 = 2235

6x = 1950

x = 325

x + 95 = 420

The speed of the planes is 325 mph and 420 mph.

5 0
3 years ago
What is f(x)= -2+7 where x= -5?
Shtirlitz [24]

Answer:

17

Step-by-step explanation:

f(x)= -2x+7

f(-5)= -2(-5)+7

              10+7

         f(-5)=17

5 0
3 years ago
Jamal is going to borrow $25,000 from his credit union to buy a used car. The APR is 7% and the length of the loan is 5 years. W
DochEvi [55]

his final charge is going to be 7

8 0
3 years ago
Answer the questions below about the quadratic function.
Korolek [52]

Given the function f(x)=3x^2-18x+23. The above function can be written as

f(x)=3x^2-18x+23\\ f(x)=3(x^2-6x)+23\\ f(x)=3(x^2-6x+9-9)+23\\ f(x)=3(x-3)^2-27+23\\ f(x)=3(x-3)^2-4

a)Now, the function f(x)=3(x-3)^2-4 has minimum value since the coefficient of (x-3)^2 is 3>0.

b) The minimum value of the function occurs at x=3 and its value is

f(3)=3(3-3)^2-4 =-4

c)The minimum value of the function occurs at x=3.

6 0
3 years ago
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