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mihalych1998 [28]
3 years ago
7

If the factors of function f are (x - 6) and (x - 1), what are the zeros of function f?

Mathematics
1 answer:
lidiya [134]3 years ago
7 0
X=6 and x=1

You can find your zeros by determining what you have to plug into the function in order for it to equal zero

If we plug in 6, for example we’d get (6-6)(x-1)

Simplified this is 0(x-1)

Anything times 0 is 0, so this is one of our zeros.

Same goes for x-1, we just need to plug in 1 for it to equal 0

Therefore there are zeros at x=1 and x=6 :))
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A manufacturer of banana chips would like to know whether its bag filling machine works correctly at the 430 gram setting. It is
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Answer:

Null Hypothesis, H_0 : \mu \geq 430 gram   {means that the machine is not under filling the bags}

Alternate Hypothesis, H_A : \mu < 430 gram   {means that the machine is under filling the bags}

Step-by-step explanation:

We are given that a manufacturer of banana chips would like to know whether its bag filling machine works correctly at the 430 gram setting.

It is believed that the machine is under filling the bags. A 21 bag sample had a mean of 429 grams with a variance of 289.

<u><em>Let </em></u>\mu<u><em> = mean weight bag filling capacity of machine.</em></u>

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Alternate Hypothesis, H_A : \mu < 430 gram   {means that the machine is under filling the bags}

The test statistics that will be used here is <u>One-sample t test statistics</u> as we don't know about the population standard deviation;

                        T.S.  = \frac{\bar X -\mu}{\frac{s}{\sqrt{n} } }  ~ t_n_-_1

where, \bar X = sample mean = 429 grams

             s = sample standard deviation = \sqrt{289} = 17 grams

             n = sample of bags = 21

So, <u><em>test statistics</em></u>  =  \frac{429-430}{\frac{17}{\sqrt{21} } }  ~ t_2_0   

                               =  -0.269

<em>Now at 0.01 significance level, the t table gives </em><u><em>critical value of -2.528 at 20 degree of freedom</em></u><em> for left-tailed test. Since our test statistics is higher than the critical value of t as -0.269 > -2.528, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which </em><u><em>we fail to reject our null hypothesis</em></u><em>.</em>

Therefore, we conclude that the machine is not under filling the bags.

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