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4 years ago

What is 5 2/3 times 3 1/4

Mathematics

2 answers:

Ira Lisetskai [31]4 years ago

6 0

Answer:

18 5/12 is the answer.

Step-by-step explanation:

Sauron [17]4 years ago

4 0

Answer:

18 and 5/12

Step-by-step explanation:

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Here is another question 9 hundreds+2000+1<br><br> 0,1,2,9

svp [43]

2901 will be your answer

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3 years ago

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You take a package to the local shipping company. They charge $0.72 per pound, and also has a fixed cost of $5

podryga [215]

Answer:

yoy didnt put a picture of the answer choices, so I'm not sure which one this would be, but the answer would be C=5 + .72P

Step-by-step explanation:

C is the total cost, so that would be on the opposite side of the equal sign from P. the 5 would be the constant, since that is the starting price for all packages, and the .72 is the price per pound, so you would have to multiply .72 by P pounds in order to complete the equation.

Hope this helps!

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4 years ago

WHAT IS THE GCF OF 270,300,252?

jasenka [17]

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3 years ago

Can someone please helppp me idk if this is correct

Sonbull [250]

The figure is a square

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3 years ago

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An ectopic pregnancy is twice as likely to develop when the pregnant woman is a smoker as it iswhen she is a nonsmoker. If 32 pe

Dmitriy789 [7]

Answer:

48.48%

Step-by-step explanation:

Let's assume that there is a number N of women.

32% of these are smokers, then there are 0.32*N smokers

then 68% of these are non-smokers, then there are 0.68*N non-smokers.

Let's assume that the probability of having a ectopic pregnancy for a non-smoker is p (and the probability for a smoker will be 2*p)

Then the number of women with an ectopic pregnancy that are non-smokers is:

p*0.68*N

The number of women with an ectopic pregnancy that are smokers is:

2*p*0.32*N

Then the total number of women with an ectopic pregnancy will be:

p*0.68*N + 2*p*0.32*N

The percentage of women having an ectopic pregnancy that are smokers is equal to the quotient between the number of women with an ectopic pregnancy that are smokers and the total number of women with an ectopic pregnancy, all that times 100%.

The percentage is:

$P = \frac{2*p*0.32*N}{p*0.68*N + 2*p*0.32*N} *100\%$

Taking p and N as common factors, we get:

$P = \frac{2*p*0.32*N}{p*0.68*N + 2*p*0.32*N} *100\% = \frac{N*p}{N*p} \frac{2*0.32}{0.68 + 2*0.32} *100\%$

Then we get:

$\frac{2*0.32}{0.68 + 2*0.32} *100\% = 48.48\%$

8 0

3 years ago