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bonufazy [111]
4 years ago
7

If a plane slices a rectangular prism through three points that are equidistant from one of its vertices,which of the following

best describes the cross-section of the prism
Mathematics
1 answer:
vagabundo [1.1K]4 years ago
5 0
Answer: An equilateral triangle would be formed.

First, imagine that you have a cube and are looking at one of the corners (vertices). Measure down the three sides from the corner the same distance.

Next, imagine that you take a knife and cut a straight plane through those points. The result of your cross section would be an equilateral triangle.
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Suppose Z has a normal distribution with a mean of 10.0 and a standard deviation of 5.0 what is the P(2.0
il63 [147K]

Answer:

.0548

Step-by-step explanation:

(2-10)/5= -1.6

go to a ztable and get .0548

4 0
3 years ago
Please help me thanks
Alexxx [7]

Answer:

A. 1.609344 km

B. 0.62137119 m

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Malory rode her bicycle 54 miles in 4.5 hours , at the rate how far can she ride in 6 hours
igomit [66]
First, we divide 54 by 4.5 to find out how many miles she can ride in 1 hour, then multiply that to 6 to find how many miles she can ride in 6 hours. 54 / 4.5 = 12, and 12 x 6 = 72, so she can ride 72 miles in 6 hours. :)
4 0
3 years ago
Read 2 more answers
Indicate the method you would use to prove the two 's . If no method applies, enter "none".
Andrei [34K]
Answer: ASA method must be applied to the given triangles to prove then congruent.


In two triangles, if two angles and their included side are congruent then the two triangles are said to be congruent .This method is known as Angle-Side -Angle postulate(ASA).
In the given triangles one side with their corresponding angles are equal. Therefore by ASA postulate they are congruent.
There we can see no other sides are given equal therefore all the other options cannot be applied.

you are lucky I had this test yesterday and I have the answer is ASA my math teacher said it was fine
6 0
3 years ago
A recent survey of 51 students reported that the average amount of time they spent listening to music was 11.5 hours per week, w
charle [14.2K]

Answer:

90% confidence interval for the mean time per week spent listening to the radio is  11.5 \pm 1.676 \times \frac{9.2}{\sqrt{51} } .

Step-by-step explanation:

We are given that a recent survey of 51 students reported that the average amount of time they spent listening to music was 11.5 hours per week, with a sample standard deviation of 9.2 hours.

Firstly, the pivotal quantity for 90% confidence interval for the population mean is given by;

                          P.Q. = \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }  ~ t_n_-_1

where, \bar X = sample average amount of time spent listening to music = 11.5

             s = sample standard deviation = 9.2 hours

             n = sample of students = 51

             \mu = population mean per week spent listening to the radio

<em>Here for constructing 90% confidence interval we have used One-sample t test statistics as we know don't about population standard deviation.</em>

<em />

So, 90% confidence interval for the population mean, \mu is ;

P(-1.676 < t_5_0 < 1.676) = 0.90  {As the critical value of t at 50 degree of

                                        freedom are -1.676 & 1.676 with P = 5%}  

P(-1.676 < \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } } < 1.676) = 0.90

P( -1.676 \times {\frac{s}{\sqrt{n} } } < {\bar X-\mu} < 1.676 \times {\frac{s}{\sqrt{n} } } ) = 0.90

P( \bar X-1.676 \times {\frac{s}{\sqrt{n} } } < \mu < \bar X+1.676 \times {\frac{s}{\sqrt{n} } } ) = 0.90

<u><em>90% confidence interval for</em></u> \mu = [ \bar X-1.676 \times {\frac{s}{\sqrt{n} } } , \bar X+1.676 \times {\frac{s}{\sqrt{n} } } ]

                  = [ 11.5-1.676 \times {\frac{9.2}{\sqrt{51} } } , 11.5+1.676 \times {\frac{9.2}{\sqrt{51} } } ]

                  = [9.34 hours , 13.66 hours]

Therefore, 90% confidence interval for the mean time per week spent listening to the radio is [9.34 hours , 13.66 hours].

4 0
3 years ago
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