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kifflom [539]
3 years ago
14

Please show the work as well 5TH GRADE MATH

Mathematics
2 answers:
Liono4ka [1.6K]3 years ago
3 0

Answer:

9450 {m}^{3}

Step-by-step explanation:

<em><u>Given</u></em><em><u> </u></em><em><u>,</u></em>

Length of the tank = 27m

Width of the tank = 35m

Depth of the tank = 10m

<em><u>Therefore</u></em><em><u>, </u></em>

Volume of the tank = <em>Length</em><em> </em><em>×</em><em> </em><em>Width</em><em> </em><em>×</em><em> </em><em>Depth</em>

= 27m × 35m × 10m

= 9450 {m}^{3} (ans)

pav-90 [236]3 years ago
3 0

Answer:

9450

Step-by-step explanation:

volume = length x width x height=27 x 35 x 10

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Please solve the following question.
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The confidence interval for the difference p1 - p2 of the population proportion is (0.063, 0.329)

<h3>How to determine the confidence interval?</h3>

The given parameters are:

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p₁ = 0.814;  p₂ = 0.618

The critical value at 95% confidence interval is

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So, we have:

CI = (p_1 - p_2) \pm z * \sqrt{\frac{p_1(1  - p_1}{n_1} + \frac{p_2(1 - p_2)}{n_2}}

Substitute known values in the above equation

CI = (0.814 - 0.618) \pm 1.96 * \sqrt{\frac{0.814 * (1  - 0.814)}{93} + \frac{0.618 * (1 - 0.618)}{80}}

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CI = 0.196 \pm 1.96 * \sqrt{0.001628 + 0.00295095}

This gives

CI = 0.196 ± 0.133

Expand

CI = (0.196 - 0.133, 0.196 + 0.133)

Evaluate

CI = (0.063, 0.329)

Hence, the confidence interval is (0.063, 0.329)

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brainly.com/question/15712887

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