Answer:(a)x^2+2y^2=2
(b)In the attached diagram
Step-by-step explanation:Step 1: Multiply both equations by t
xt=t(cost -sint)\\ty\sqrt{2} =t(cost +sint)
Step 1: Multiply both equations by t
xt=t(cost -sint)\\ty\sqrt{2} =t(cost +sint)
Step 2:We square both equations
(xt)^2=t^2(cost -sint)^2\\(ty)^2(\sqrt{2})^2 =t^2(cost +sint)^2
Step 3: Adding the two equations
(xt)^2+(ty)^2(\sqrt{2})^2=t^2(cost -sint)^2+t^2(cost +sint)^2\\t^2(x^2+2y^2)=t^2((cost -sint)^2+(cost +sint)^2)\\x^2+2y^2=(cost -sint)^2+(cost +sint)^2\\(cost -sint)^2+(cost +sint)^2=2\\x^2+2y^2=2 hopes this helps
4.415e+8
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Answer: x=−9/4
Step-by-step explanation:
Let's solve your equation step-by-step.
−2(x+14)+1=5
Step 1: Simplify both sides of the equation.
−2(x+14)+1=5(−2)(x)+(−2)(14)+1=5(Distribute)−2x+
−1
2
+1=5
(−2x)+(
−1
2
+1)=5(Combine Like Terms)
−2x+
1
2
=5
−2x+
1
2
=5
Step 2: Subtract 1/2 from both sides.
−2x+
1
2
−
1
2
=5−
1
2
−2x=
9
2
Step 3: Divide both sides by -2.
−2x
−2
=
9
2
−2
x=
−9
4
<span>The correct answer to your question is... a rational #, because w</span><span>hen you add two rational #'s, each # can be written as a rational #.
</span><span>
Reasoning:
So, adding two rational #'s like adding fractions will result in another fraction of this same form since integers are closed under + and x. Thus, adding two rational #'s produces another rational #.
By the way # means number.
</span>I hope this helps!
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