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1 year ago

If tu=18 and u=11 what is tv

Mathematics

1 answer:

yuradex [85]1 year ago

8 0

If the point U is between points T and V, then the numerical length of TV is 29 units

<h3>How to determine the numerical length of segment TV?</h3>

From the question, we have the following lengths that can be used in our computation:

Length TU = 18 units
Length UV = 11 units

The above parameters and representations implies that the point U is between endpoints T and V

This also means that the length TV is longer than the other lengths TU and TV

So, we have the following length equation

TV = TU + UV

Substitute the known values in the above equation

So, we have the following equation

TV = 18 + 11

Evaluate the sum of the like terms in the above equation

So, we have the following equation

TV = 29

Hence, the numerical length of segment TV is 29 units

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Read 2 more answers

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bija089 [108]

The solutions are $(\sqrt{2},-1) \text { and }(-\sqrt{2},-1)$ .

Solution:

Given equation:

$-2 x^{2}+y=-5$

Add $2 x^{2}$ on both sides.

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Equate (1) and (2).

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Add $3 x^{2}$ on both sides.

$-5+2 x^{2}+3 x^{2}=-3 x^{2}+5 +3 x^{2}$

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Add 5 on both sides.

$-5+5x^{2}+5=5+5$

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Divide by 5 on both sides, we get

$x^{2}=2$

Taking square root on both sides, we get

$x=\sqrt{2}, x=-\sqrt{2}$

Substitute $x=\sqrt{2}$ in (1).

$y=-5+2(\sqrt{2})^2$

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Substitute $x=-\sqrt{2}$ in (1).

$y=-5+2(-\sqrt{2})^2$

$y=-5+4$

$y=-1$

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Option C is the correct answer.

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