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3 years ago

Select all the answers !

Mathematics

1 answer:

ki77a [65]3 years ago

3 0

Answer:

1,3 and 4

it is what it be

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Find the value of x and 2x

olga2289 [7]

X is 15 and X2 is 30

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3 years ago

2. Kembangkan; (a) 3(7 – a) (b) (x + 4) (x – 4) (c) 8n(–3 – 2n2)

snow_tiger [21]

Answer:

A) 21 - 3a

B) x^2 - 16

C) - 24n - 16n3

6 0

3 years ago

Are they like terms? 3x & -x

Setler [38]

Yea cuz they both have x

8 0

3 years ago

What is the difference?

Whitepunk [10]

Answer:

$\frac{x^2+3x -12}{(x-5) (x +3)(x+7)}$

Step-by-step explanation:

Given

$\frac{x}{x^2-2x-15} - \frac{4}{x^2+2x-35}$

Required

Calculate the difference

We start by factorizing the denominator of both fractions

$\frac{x}{x^2-2x-15} - \frac{4}{x^2+2x-35}$

$\frac{x}{x^2+3x - 5x -15} - \frac{4}{x^2+7x - 5x-35}$

$\frac{x}{x(x+3) - 5(x +3)} - \frac{4}{x(x+7) - 5(x+7)}$

$\frac{x}{(x-5) (x +3)} - \frac{4}{(x-5)(x+7)}$

Take LCM

$\frac{x(x+7) - 4(x +3)}{(x-5) (x +3)(x+7)}$

Open Brackets

$\frac{x^2+7x - 4x -12}{(x-5) (x +3)(x+7)}$

$\frac{x^2+3x -12}{(x-5) (x +3)(x+7)}$

This can't be simplified any further;

4 0

3 years ago

For the dinner special at a restaurant, the customer must choose an appetizer, an entree, a side dish, and a dessert.

gtnhenbr [62]

Answer:

3 dinner specials are possible to make.

Step-by-step explanation:

you group 4 things up, 1 from each category then you have your groups when you can't group 4!

Which results in the answer- 3 dinner specials!

8 0

2 years ago