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4 years ago

Write the equation of a line that goes through point (0,1) and has a slope of 0

Mathematics

1 answer:

8090 [49]4 years ago

5 0

Answer:

$1 = y$

Step-by-step explanation:

The y-intercept is [0, 1], so you draw a horizontal line through the line $y = 1.$ , which is considered a zero slope [rate of change].

I am joyous to assist you anytime.

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Solve for x (1/x) -2/3 = (4x)

Vadim26 [7]

The value of x is $x=\frac{-1+\sqrt{37}}{12}$ and $x=\frac{-1-\sqrt{37}}{12}$

Step-by-step explanation:

The equation is $\frac{1}{x}-\frac{2}{3}=4 x$

Subtracting by $4x$ on both sides,

$\frac{1}{x}-\frac{2}{3}-4 x=0$

Taking LCM,

$\frac{3-12 x^{2}-2 x}{3 x}=0$

Multiplying by 3x on both sides,

$-12 x^{2}-2 x+3=0$

Dividing by (-) on both sides,

$12 x^{2}+2 x-3=0$

Using quadratic formula, we can solve for x.

$\begin{aligned}x &=\frac{-2 \pm \sqrt{2^{2}-4 \cdot 12 \cdot(-3)}}{2 \cdot 12} \\&=\frac{-2 \pm \sqrt{4+144}}{2 \cdot 144} \\&=\frac{-2 \pm \sqrt{148}}{24} \\&=\frac{-2 \pm 2 \sqrt{37}}{24}\end{aligned}$

Taking out common term 2, we get,

$\begin{array}{l}{x=\frac{-2(1 \pm \sqrt{37})}{24}} \\{x=\frac{-1 \pm \sqrt{37}}{12}}\end{array}$

Thus, the value of x is $x=\frac{-1+\sqrt{37}}{12}$ and $x=\frac{-1-\sqrt{37}}{12}$

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3 years ago

Tara worked on her science fair project for 4 hours every day for 4 days. Which is the best

nirvana33 [79]

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What is the slope of the line passing through the points (1, 2) and (5, 4)?

bulgar [2K]

<h2>SOLVING</h2>

$\Large\maltese\underline{\textsf{A. What is Asked}}$

What is the slope of the line passing through the point (1,2) and (5,4)

$\Large\maltese\underline{\textsf{This problem has been solved!}}$

Formula used, here $\bf{\dfrac{y2-y1}{x2-x1}$

_______________________________________________________

$\bf{\dfrac{4-2}{5-1}$ | simplify

$\bf{\dfrac{2}{4}$ | reduce

$\bf{\dfrac{1}{2}$

$\rule{300}{1.7}$

$\bf{Result:}$

$\bf{=Slope:\dfrac{1}{2}$

$\boxed{\bf{aesthetic\not101}}$

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