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3 years ago

Where is the best place to learn spanish for free and become fluent on line

Mathematics

2 answers:

nataly862011 [7]3 years ago

7 0

I would say duolingo. it's an app, not a website though

liraira [26]3 years ago

7 0

Answer:

DUOLINGOOOO

Step-by-step explanation:

keeps you persistent through notifications so turn it on

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PLEASE HELP been stuck on this for a while

marysya [2.9K]

Answer:

I believe it's D but I'm not 100 percent sure. I hope this helped I'm sorry I couldn't help more <3

4 0

3 years ago

The figure shows three exterior angles of triangle ABC. Show that the measure of angle 1 plus the measure of angle 2 plus the me

ivolga24 [154]

Step-by-step explanation:

Let the angle near point A be $A$ .

Let the angle near point B be $B$ .

Let the angle near point C be $C$ .

Let the external angle near point A be $extA$ .

Let the external angle near point B be $extB$ .

Let the external angle near point C be $extC$ .

According to exterior angle property,exterior angle of an angle is the sum of other two angles.

So,

$extA=B+C\\extB=A+C\\extC=A+B$

According to angle sum property,the sum of angles in the triangle add to $180$

$extA+extB+extC=B+C+A+C+A+B=2(A+B+C)=2\times 180=360^{0}$

3 0

3 years ago

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Can you help with this math please?

Blababa [14]

Answer:

3 on the other side and 7 and 7 on the sides

Step-by-step explanation:

3 0

3 years ago

What is the square root of 16x^<br> 36?

Vsevolod [243]

Note that $\sqrt[2]{x}=x^{\frac{1}{2}}$

$\sqrt[2]{16x^{36}}=\sqrt[2]{4^2x^{18\cdot2}}$

$4^{2\cdot\frac{1}{2}}x^{18\cdot2\cdot\frac{1}{2}}=4^{\frac{2}{2}}x^{\frac{18\cdot2}{2}}$

$\boxed{4x^{18}}$

Hope this helps.

r3t40

4 0

3 years ago

What is the solution to the equation -3d/a^2-2d-8 + 3/d-4 = -2/ d+2

Alex73 [517]

Answer:

d=1

Step-by-step explanation:

$\frac{-3d}{d^2-2d-8} +\frac{3}{d-4} =\frac{-2}{d+2}$

Lets factor the denominator d^2 -2d-8

d^2 - 2d - 8 = (d-4)(d+2)

$\frac{-3d}{(d-4)(d+2)} +\frac{3}{d-4} =\frac{-2}{d+2}$

Now make the denominators same

LCD: (d-4)(d+2)

$\frac{-3d}{(d-4)(d+2)} +\frac{3(d+2)}{(d-4)(d+2)} =\frac{-2(d-4)}{(d+2)(d-4)}$

Denominators are same on both sides

So equate the numerators

-3d +3(d+2) = -2(d-4)

-3d +3d +6 = -2d +8

6 = -2d + 8

subtract 8 on both sides

-2 = -2d

So d=1

3 0

3 years ago

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