Answer:
No.
Step-by-step explanation:
If we were to fill in the slots, the equation would be...
6x3-18=4
6 times three is 18, and 18 - 18 equals 0. So the answer would not be 1.
Slope intercept form of a line passing through (-1, -2) and (1, -4) is ![y= -x-3.](https://tex.z-dn.net/?f=y%3D%20-x-3.)
<u>
Solution:
</u>
We have to find the equation of a line in slope intercept form.
Given that
Line is passing through point (− 1, − 2) and (1, − 4).
Equation of line passing through point
and
is given by,
![y-y_{1}=\frac{\left(y_{2}-y_{1}\right)}{\left(x_{2}-x_{1}\right)}\left(x-x_{1}\right) \Rightarrow(1)](https://tex.z-dn.net/?f=y-y_%7B1%7D%3D%5Cfrac%7B%5Cleft%28y_%7B2%7D-y_%7B1%7D%5Cright%29%7D%7B%5Cleft%28x_%7B2%7D-x_%7B1%7D%5Cright%29%7D%5Cleft%28x-x_%7B1%7D%5Cright%29%20%5CRightarrow%281%29)
In our case ![x_{1}=-1, y_{1}=-2, x_{2}=1, y_{2}=-4](https://tex.z-dn.net/?f=x_%7B1%7D%3D-1%2C%20y_%7B1%7D%3D-2%2C%20x_%7B2%7D%3D1%2C%20y_%7B2%7D%3D-4)
Substituting given value in (1) we get
,
![\begin{array}{l}{\Rightarrow y-(-2)=\frac{(-4-(-2))}{(1-(-1))}(x-(-1))} \\\\ {\Rightarrow y+2=-\frac{2}{2}(x+1)} \\\\ {\Rightarrow y+2=-1(x+1)} \\\\ {\Rightarrow y+2=-x-1} \\\\ {\Rightarrow y=-x-1-2} \\\\ {\Rightarrow y=-x-3}\end{array}](https://tex.z-dn.net/?f=%5Cbegin%7Barray%7D%7Bl%7D%7B%5CRightarrow%20y-%28-2%29%3D%5Cfrac%7B%28-4-%28-2%29%29%7D%7B%281-%28-1%29%29%7D%28x-%28-1%29%29%7D%20%5C%5C%5C%5C%20%7B%5CRightarrow%20y%2B2%3D-%5Cfrac%7B2%7D%7B2%7D%28x%2B1%29%7D%20%5C%5C%5C%5C%20%7B%5CRightarrow%20y%2B2%3D-1%28x%2B1%29%7D%20%5C%5C%5C%5C%20%7B%5CRightarrow%20y%2B2%3D-x-1%7D%20%5C%5C%5C%5C%20%7B%5CRightarrow%20y%3D-x-1-2%7D%20%5C%5C%5C%5C%20%7B%5CRightarrow%20y%3D-x-3%7D%5Cend%7Barray%7D)
Hence slope intercept form of a line passing through (-1, -2) and (1, -4) is ![y= -x-3](https://tex.z-dn.net/?f=y%3D%20-x-3)
Answer:
1.2
Step-by-step explanation:
1. Set up the long division.
2. Calculate 3 ÷ 3, which is 1.
3. Bring down 6, so that 6 is large enough to be divided by 3.
4. Calculate 6 ÷ 3, which is 2.
5. Therefore, 3.6 ÷ 3 = 1.2
Hope this helps :)