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3 years ago

45 POINTS WILL PICK BRAINLIEST

Mathematics

2 answers:

jonny [76]3 years ago

6 0

The answer to your question is c :)

Karolina [17]3 years ago

5 0

Answer:

Step-by-step explanation:

triangle XYZ is doubled the triangle of ABC. if you were to divide XYC by 2, you would get the same lengths of ABC. therefore, they are similar. not quite congruent

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What is the range of the function shown on the graph?

never [62]

Answer:

$y \in \{\space \mathbb R \space| -6 < y < \infty\}$

Step-by-step explanation:

We can see from the graph that $y$ can't be lesser than $-6$ and $y$ extends unendlessly in the positive direction.

4 0

3 years ago

Factor tree for 30 and 54

elena-14-01-66 [18.8K]

Answer:

30|2

15|3

5|5

54|2

27|3

9|3

3|3

5 0

4 years ago

Read 2 more answers

The volume of a cube shaped shipping container is 2744 in.³ find the edge length of the shipping container

Dima020 [189]

Answer:

The edge length of the shipping container is 14 in.

Step-by-step explanation:

The volume enclosed by a cube is the number of cubic units that will exactly fill a cube.

To find the volume of a cube we need to recall that a cube has all edges the same length. The volume of a cube is found by multiplying the length of any edge by itself twice. Or as a formula:

$V=s^3$

where, <em>s</em> is the length of any edge of the cube.

To find the edge length of the shipping container we use the fact that the volume of a cube shaped shipping container is 2744 in³ and the above formula.

$2744=s^3\\\\s^3=2744\\\\s=\sqrt[3]{2744}\\\\s = 14\:in$

7 0

3 years ago

Which of the following is the general solution of the differential equation dy dx equals the quotient of 4 times x and y?

katovenus [111]

The ODE appears to be

$\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{4x}y$

It's separable; we can write

$y\,\mathrm dy=4x\,\mathrm dx$

and integrating both sides yields

$\dfrac{y^2}2=2x^2+C$

$\implies y^2=4x^2+C$

7 0

3 years ago

23 degrees 20’48 is the same as _degrees.

allochka39001 [22]

Answer:

$\large\boxed{23^o20'48''=\left(23\dfrac{26}{75}\right)^o}$

Step-by-step explanation:

$\text{We know:}\\\\1^o=60'\to1'=\left(\dfrac{1}{60}\right)^o\\\\1'=60''\to1^o=(60)(60'')=3600''\to1''=\left(\dfrac{1}{3600}\right)^o\\\\23^o20'48''\\\\20'=\left(\dfrac{20}{60}\right)^o=\left(\dfrac{1}{3}\right)^o\\\\48''=\left(\dfrac{48}{3600}\right)^o=\left(\dfrac{1}{75}\right)^o\\\\\text{Therefore}\\\\23^o20'48''=23^o+20'+48''=23^o+\left(\dfrac{1}{3}\right)^o+\left(\dfrac{1}{75}\right)^o\\\\=\left(23+\dfrac{1\cdot25}{3\cdot75}+\dfrac{1}{75}\right)^o=\left(23+\dfrac{25}{75}+\dfrac{1}{75}\right)^o=\left(23\dfrac{26}{75}\right)^o$

4 0

4 years ago