Ask question

Ask question

All categories

3 years ago

12

Please help I will Mark brainlyist

1 answer:

mart [117]3 years ago

7 0

Answer:

1=4

2=2

3=2

4=15

5=5-25

6=6

7=5 and 4

Step-by-step explanation:

You might be interested in

Add or Subtract.<br> 7/24 - 5/36

lisov135 [29]

Answer:

A product of a number and 12 is increased by 23

8 0

1 year ago

What is a numerator and a denominator

victus00 [196]

The numerator is the top of the fraction and the denominator is the bottom of the fraction, so for example if 4/5 is the fraction, then the numerator would be 4 and the denominator would be 5.

Hope this is what you were looking for!!!

~Shane

4 0

3 years ago

Read 2 more answers

Find S9, the sum of the geometric series to the 9th term, in which a3=3.645 and a8=15

ArbitrLikvidat [17]

Answer:

The sum of the first nine terms of the sequence is 74.44.

Step-by-step explanation:

Geometric sequence concepts:

The nth term of a geometric sequence is given by the following equation.

$a_{n+1} = ra_{n}$

In which r is the common ratio.

This can be expanded for the nth term in the following way:

$a_{n} = a_{1}r^{n-1}$

In which $a_{1}$ is the first term.

Or even:

$a_{n} = a_{m}r^{n-m}$

The sum of the first n terms of a geometric sequence is given by:

$S_{n} = \frac{a_{1}(1 - r^{n})}{1 - r}$

Finding the common ratio:

$a_{3} = 3.645, a_{8} = 15$

$a_{n} = a_{m}r^{n-m}$

$a_{8} = a_{3}r^{8-3}$

$a_{3}r^{5} = a_{8}$

$3.645r^{5} = 15$

$r^{5} = \frac{15}{3.645}$

$r = \sqrt[5]{\frac{15}{3.645}}$

$r = 1.327$

Finding the first term:

$a_{3} = a_{1}r^{2}$

$a_{1} = \frac{a_{3}}{r^{2}}$

$a_{1} = \frac{3.645}{(1.327)^{2}}$

$a_{1} = 2.07$

Sum of the first nine terms:

$S_{9} = \frac{2.07*(1 - (1.327)^{9})}{1 - 1.327} = 74.44$

The sum of the first nine terms of the sequence is 74.44.

8 0

3 years ago

Read 2 more answers

The volume of water and a rectangle swimming pool can be modeled by the function v(x)=x^3+13x-210. If the depth of the pool is g

S_A_V [24]

Answer:

Required,

$L=\frac{3+\sqrt{37}}{2}-\frac{144}{x-3}$

$W=\frac{3-\sqrt{37}}{2}-\frac{144}{x-3}$

Step-by-step explanation:

Given volume and depth respectively,

$V(x)=x^3+13x-210$ and $x-3$

To find length and width of the rectanglular swiming pool we know,

Volume=length $\times$ height $\times$ depth.

Let depth=D=x-3, length=L, width=W, then

$V=DLW$

$x^3+13x-210= LW(x-3)$

$LW=\frac{x^3+13x-210}{x-3}$

After divide we will get $x^2-3x-22$ with remainder -144.

Thus,

$x^3+13x-210=(x^2-3x-22)(x-3)-144=(x-3)LW$

Now to find root of,

$x^2-3x-144=\frac{3\pm\sqrt{9+88}}{2}=\frac{3\pm \sqrt{37}}{2}$

Thus,

$L=\frac{3+\sqrt{37}}{2}-\frac{144}{x-3}$

$W=\frac{3-\sqrt{37}}{2}-\frac{144}{x-3}$

5 0

3 years ago

Francine is selling ice cream from her shack on the ocean. She opens the shack

madam [21]

Answer: The answer for that would be 325

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers