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expeople1 [14]
3 years ago
15

A long thin sample of a substance is easily bent. When the substance is placed in a n electric circuit and the switch is closed,

and LED light turns on. What type of bonding holds the particles of the substance together?
Chemistry
1 answer:
goblinko [34]3 years ago
8 0

Answer:

A metallic bonding holds the particles of the substance together

Explanation:

<em><u>The unknown substance is a metal</u></em>:

  • It is easily bent: This means it is ductile, as it is the case with a thin metallic metallic wire.
  • "When the substance is placed in a n electric circuit and the switch is closed, and LED light turns on." <em>This means it easily conducts electricity</em>. Metals are good conductors.
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6 0
4 years ago
Use the rhombus to find the measure of the following angles m
Studentka2010 [4]

DA = 13, BW = 5, WC = 12, ∠ACD = 25°, ∠DAB = 50°, ∠ADC = 130°, ∠DBC = 65° and ∠BWC = 90° given that ABCD is a rhombus and DB = 10, BC = 13, ∠WAD = 25°. This can be obtained by understanding the properties of a rhombus.

<h3>What are the required values of sides and angles?</h3>

Here in the question it is given that,

  • ABCD is a rhombus
  • DB = 10, BC = 13, ∠WAD = 25°

We have to find the values of DA, BW, WC, ∠BAC, ∠ACD, ∠DAB, ∠ADC, ∠DBC, ∠BWC.

1) Since all the sides of the rhombus are equal, DA = 13

2) Since diagonals are perpendicular bisectors of each other, BW = 5

3) Since formula of diagonal is,

d₁ = √4a² - d₂,

here a = 13, d₂ = 10

d₁ = √4×13² - 10

d₁ = √676 - 10 = √576 = 24

Since diagonals are perpendicular bisectors of each other

WC = 24/2  ⇒ WC = 12

4) Since diagonals are angle bisectors at the corners, ∠BAC = 25°

5) Since diagonals are angle bisectors at the corners,

∠BAW = ∠DAW = 25° ⇒ ∠BAD =∠BAW + ∠DAW = 25° + 25° ⇒∠BAD = 50°

Since opposite angles of the rhombus are equal,

∠BAD = ∠BCD = 50° ⇒ ∠BCW = ∠DCW = 25°

⇒ ∠ACD = 25°

6) Since diagonals are angle bisectors at the corners,∠BAW = ∠DAW = 25° ⇒ ∠BAD =∠BAW + ∠DAW = 25° + 25° ⇒∠BAD = 50°

⇒ ∠DAB = 50°

7) Since adjacent angles are supplementary angles,

∠BAD + ∠ADC = 180° ⇒ 50° + ∠ADC = 180° ⇒ ∠ADC = 180° - 50° = 130°

⇒ ∠ADC = 130°

8) Since diagonals are angle bisectors at the corners,

∠DBC = 130°/2

⇒ ∠DBC = 65°

9) Since all the sides make an angle of 90° at the center,

⇒ ∠BWC = 90°

Hence DA = 13, BW = 5, WC = 12, ∠ACD = 25°, ∠DAB = 50°, ∠ADC = 130°, ∠DBC = 65° and ∠BWC = 90° given that ABCD is a rhombus and DB = 10, BC = 13, ∠WAD = 25°.

Learn more about rhombus here:

brainly.com/question/27870968

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6 0
2 years ago
Use the drop-down menus to identify each substance as an organic or inorganic compound
dalvyx [7]

Answer:

ozone (O3): inorganic

methane (CH4): organic

aluminum hydroxide (Al(OH)3): inorganic

butane (C4H10): organic

carbon monoxide (CO): inorganic

Explanation:

An inorganic compound is typically a chemical compound that lacks carbon–hydrogen bonds, that is, a compound that is not an organic compound. Some simple compounds that contain carbon are often considered inorganic. Examples of inorganic compounds include carbon monoxide , carbon dioxide , carbonates, carbides , cyanides, cyanates, and thiocyanates. Most of these compounds are normal parts of mostly organic systems, including living organisms. When a chemical substance is classified as inorganic, it does not necessarily mean that it does not occur within

living things.

Organic compounds typically contain the carbon-hydrogen bonds. The carbon atoms often catenate and most organic substances occur in living systems and are products of biochemical reactions in living organisms. However, organic substances can also be synthetic and can be prepared in the laboratory.

6 0
3 years ago
Which statements are true? The oxidation number for Cu(s) is +2. An oxidizing agent gains electrons. Na+ is formed from the redu
just olya [345]

<u>Answer:</u> The correct statements are:

An oxidizing agent gains electrons and Zn^{2+} is formed from the oxidation of Zn(s).

<u>Explanation:</u>

For the given options:

  • <u>Statement 1</u>: The oxidation number for Cu(s) is +2

Copper is the 29th element of the periodic table having electronic configuration of [Ar]3d^{10}4s^1

This element can show +1 or +2 oxidation states. Thus, this statement is false.

  • <u>Statement 2:</u> An oxidizing agent gains electrons.

Oxidizing agents are defined as the agents which oxidize other substance and itself gets reduced. These agents undergoes reduction reactions and reduction reaction is the reaction in which an atom gains electrons.

Thus, this statement is True.

  • <u>Statement 3:</u>  Na^+ is formed from the reduction of Na(s)

Oxidation reaction is defined as the reaction in which an atom looses its electrons. Here, oxidation state of the atom increases.

X\rightarrow X^{n+}+ne^-

Sodium is the 11th element and it will loose electrons to form sodium ion.

Na\rightarrow Na^++e^-

Hence, this statement is false.

  • <u>Statement 4:</u> The oxidation number for Hg(l) is 0.

Mercury is the 80th element of the periodic tale having electronic configuration of [Xe]4f^{14}5d^{10}6s^2

This element can show +1 or +2 oxidation states. Thus, this statement is false.

  • <u>Statement 5:</u> A reducing agent gains electrons.

Reducing agents are defined as the agents which reduces the other substance and itself gets oxidized. These agents undergoes oxidation reactions and oxidation reaction is defined as the reaction in which an atom looses its electrons.

Thus, this statement is false.

  • <u>Statement 6:</u>  Zn^{2+} is formed from the oxidation of Zn(s)

Oxidation reaction is defined as the reaction in which an atom looses its electrons. Here, oxidation state of the atom increases.

X\rightarrow X^{n+}+ne^-

Zinc is the 30th element and it will loose electrons to form zinc ion.

Zn\rightarrow Zn^{2+}+2e^-

Thus, this statement is True.

Hence, the correct statements are:

An oxidizing agent gains electrons and Zn^{2+} is formed from the oxidation of Zn(s).

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3 years ago
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