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goldenfox [79]
3 years ago
12

Will mark brainly ASAP

Chemistry
1 answer:
jok3333 [9.3K]3 years ago
7 0
Shivering, because it’s just a reflex to maintain homeostasis and nothing is necessarily ‘coming out’
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Suppose 0.035 moles of HCl is dissolved in enough water to produce 750 mL of solution. What is the pH
zhuklara [117]

Answer:

pH = 1.33

Explanation:

Because HCl is a strong acid, each mole of HCl will completely dissociate into H⁺ and Cl⁻ species.

Now we calculate the molar concentration (molarity) of H⁺:

  • Molarity = moles / volume

(750 mL ⇒ 750 / 1000 = 0.750 L)

  • Molarity = 0.035 moles / 0.750 L
  • Molarity = 0.0467 M

Then we calculate the pH of the solution:

  • pH = -log [H⁺]
  • pH = -log (0.0467 M)
  • pH = 1.33
5 0
3 years ago
How much pressure does an elephant with a mass of 2200 Kg and a total footprint area of 4500 cm2 exert on the ground?
Debora [2.8K]

Answer:

47911.1 pa

Explanation:

The SI base unit of pressure is pascal, which is N/m^2.

2200 kg is 2200*9.8=21560 N, and 4500 cm^2=4500/10000=0.45 m^2.

So the total pressure exerted on the ground (!!) is 21560/0.45= 47911.1 Pa.

6 0
3 years ago
Read 2 more answers
Answer question number 2
kipiarov [429]

Answer:

it would be the second choice

3 0
3 years ago
How are conclusions and evidence related
serg [7]
You need evidence to support a conclustion 
3 0
3 years ago
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A 1.0l buffer solution contains 0.100 mol of hc2h3o2 and 0.100 mol of nac2h3o2. the value of ka for hc2h3o2 is 1.8×10−5. part a
Mandarinka [93]
There are two ways to solve this problem. We can use the ICE method which is tedious and lengthy or use the Henderson–Hasselbalch equation. This equation relates pH and the concentration of the ions in the solution. It is expressed as

pH = pKa + log [A]/[HA] 

 where pKa = - log [Ka]
[A] is the concentration of the conjugate base
[HA] is the concentration of the acid

Given:
Ka = 1.8x10^-5
NaOH added = 0.015 mol
HC2H3O2 = 0.1 mol
NaC2H3O2 = 0.1 mol

Solution:
pKa = - log ( 1.8x10^-5) = 4.74

[A] = 0.015 mol + 0.100 mol = .115 moles
[HA] = .1 - 0.015 = 0.085 moles

pH = 4.74 + log (.115/0.085)
pH = 4.87
6 0
3 years ago
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