Question

Write y=2x^2-12x+16 in vertex form

Answer 1

Answer:

y = 2$(x - 3)^{2}$ - 1

Step-by-step explanation:

y = 2$x^{2}$ - 12x + 16  

y = 2($x^{2}$ - 6x + 8)        ( Factor out 2 )

y + 9= 2($x^{2}$ - 6x + 9) + 8 ( Complete the square $(\frac{-b}{2} )^{2}$ ) Add 9 both sides  

y + 9 = 2 $(x - 3)^{2}$ + 8      (Subtract 9 each side)  

y = 2 $(x - 3) ^{2}$ - 1         ( simplify )