Answer: Coterminal Angles are angles who share the same initial side and terminal sides. Finding coterminal angles is as simple as adding or subtracting 360° or 2π to each angle, depending on whether the given angle is in degrees or radians.
Answer:
right
Step-by-step explanation:
32/8=4
(m^5)(m^-3)=m^2
Answer:
Area pf the regular pentagon is 193
to the nearest whole number
Step-by-step explanation:
In this question, we are tasked with calculating the area of a regular pentagon, given the apothem and the perimeter
Mathematically, the area of a regular pentagon given the apothem and the perimeter can be calculated using the formula below;
Area of regular pentagon = 1/2 × apothem × perimeter
From the question, we can identify that the value of the apothem is 7.3 inches, while the value of the perimeter is 53 inches
We plug these values into the equation above to get;
Area = 1/2 × 7.3× 53 = 386.9/2 = 193.45 which is 193
to the nearest whole number
Answer:
A) ![\displaystyle \int\limits^3_0 {\frac{x + 1}{3x - 2}} \, dx](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cint%5Climits%5E3_0%20%7B%5Cfrac%7Bx%20%2B%201%7D%7B3x%20-%202%7D%7D%20%5C%2C%20dx)
General Formulas and Concepts:
<u>Calculus</u>
Discontinuities
- Removable (Hole)
- Jump
- Infinite (Asymptote)
Integration
- Integrals
- Definite Integrals
- Integration Constant C
- Improper Integrals
Step-by-step explanation:
Let's define our answer choices:
A) ![\displaystyle \int\limits^3_0 {\frac{x + 1}{3x - 2}} \, dx](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cint%5Climits%5E3_0%20%7B%5Cfrac%7Bx%20%2B%201%7D%7B3x%20-%202%7D%7D%20%5C%2C%20dx)
B) ![\displaystyle \int\limits^3_1 {\frac{x + 1}{3x - 2}} \, dx](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cint%5Climits%5E3_1%20%7B%5Cfrac%7Bx%20%2B%201%7D%7B3x%20-%202%7D%7D%20%5C%2C%20dx)
C) ![\displaystyle \int\limits^0_{-1} {\frac{x + 1}{3x - 2}} \, dx](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cint%5Climits%5E0_%7B-1%7D%20%7B%5Cfrac%7Bx%20%2B%201%7D%7B3x%20-%202%7D%7D%20%5C%2C%20dx)
D) None of these
We can see that we would have a infinite discontinuity if x = 2/3, as it would make the denominator 0 and we cannot divide by 0. Therefore, any interval that includes the value 2/3 would have to be rewritten and evaluated as an improper integral.
Of all the answer choices, we can see that A's bounds of integration (interval) includes x = 2/3.
∴ our answer is A.
Topic: AP Calculus AB/BC (Calculus I/I + II)
Unit: Integration
Book: College Calculus 10e