Answer:
The tank must remain intact for 1183 years.
Step-by-step explanation:
Exponential equation for decay:
The amount of a substance after t years is given by:
In which A(0) is the initial amount and r is the decay rate.
A storage tank contains a liquid radioactive element with a half-life of 96 years.
This means that 
, and we use this to find r.
So
It will be relatively safe for the contents to leak from the tank when 0.02% of the radioactive element remains. How long must the tank remain intact for this storage procedure to be safe?
This is t for which 
. So
The tank must remain intact for 1183 years.
Answer:
- as written, -2
- with denominator parentheses, 0
- with f(x)=ln(x) and denominator parentheses, -1/2
Step-by-step explanation:
The problem as stated asks for the limit as x approaches 2 of (0/x) -2.
As written, the limit is (0/2) -2 = -2.
<u>Explanation</u>: f(x) is a constant, so the numerator is 0. The ratio 0/x -2 is defined as -2 everywhere except x=0. So, the value at x=2 is 0/2 -2 = -2.
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If you mean (f(2) -f(x))/(x -2), that limit is the limit of 0/(x-2) = 0 as x approaches 2.
<u>Explanation</u>: f(x) is a constant, so the numerator is 0. The ratio 0/(x-2) is zero everywhere except at x=2. The left limit and right limit are both 0 as x approaches 2. Since these limits agree, the limit is said to be 0.
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If you mean f(x) = ln(x) and you want the limit of (f(2) -f(x))/(x -2), that value will be -1/2.
<u>Explanation</u>: The value of the ratio is 0/0 at x=2, so we can find the limit using L'Hôpital's rule. Differentiating numerator and denominator, we have ...
lim = (-1/x)/(1)
The value is -1/2 at x=2.
Answer:
(5x-1)(6x^2+1)
Solution:
6x^2(5x-1)+5x-1
=30x^3-6x^2+5x-1
=(30x^3-6x^2) + (5x-1)
=6x^2(5x-1)+(5x-1)
=(5x-1)(6x^2+1)
HOPE THIS HELPS!
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your answer is C!
<span>the triangle inequality theorem simply states, The sum of the lengths of any two sides of a triangle is greater than the length of the third side. your answer is B.</span>
