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sergejj [24]
3 years ago
11

If f(x) = ln(2), then limx--->2 (f(2)-f(x))/x-2

Mathematics
1 answer:
Blizzard [7]3 years ago
7 0

Answer:

  • as written, -2
  • with denominator parentheses, 0
  • with f(x)=ln(x) and denominator parentheses, -1/2

Step-by-step explanation:

The problem as stated asks for the limit as x approaches 2 of (0/x) -2.

As written, the limit is (0/2) -2 = -2.

<u>Explanation</u>: f(x) is a constant, so the numerator is 0. The ratio 0/x -2 is defined as -2 everywhere except x=0. So, the value at x=2 is 0/2 -2 = -2.

__

If you mean (f(2) -f(x))/(x -2), that limit is the limit of 0/(x-2) = 0 as x approaches 2.

<u>Explanation</u>: f(x) is a constant, so the numerator is 0. The ratio 0/(x-2) is zero everywhere except at x=2. The left limit and right limit are both 0 as x approaches 2. Since these limits agree, the limit is said to be 0.

__

If you mean f(x) = ln(x) and you want the limit of (f(2) -f(x))/(x -2), that value will be -1/2.

<u>Explanation</u>: The value of the ratio is 0/0 at x=2, so we can find the limit using L'Hôpital's rule. Differentiating numerator and denominator, we have ...

  lim = (-1/x)/(1)

The value is -1/2 at x=2.

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Answer:

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Step-by-step explanation:

The price with tax included is ...

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Step-by-step explanation:

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On a quiz, you answered 38 questions correctly out of 43. What percent did you answer correctly? (Round your answer to nearest p
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Step-by-step explanation:

Use FOIL:

y^4 + \frac{-14}{5}y^2 + \frac{5}{7}y^2 + \frac{-70}{35}

Make  \frac{-14}{5}y^2 and \frac{5}{7}y^2 have the same numerator:

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Then add like terms and simplify:

y^4 + \frac{-98}{35}y^2 + \frac{25}{35} y^2 + \frac{-70}{35}

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3 years ago
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