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Lady_Fox [76]
3 years ago
14

A store sells cooking oil of two different brands in bottles of the same size. The table below and the equation each show the pr

ice (y), in dollars, of different number of bottles of oil (x): Brand A Number of Bottles, x Price (dollars), y 2 26 3 39 4 52 5 65 Brand B y = 16x How many dollars more is the price of 7 bottles of brand B oil than the price of 7 bottles of brand A oil? $3 $10 $21 $29 my answer keeps coming out to 34
Mathematics
2 answers:
Strike441 [17]3 years ago
6 0

Answer:

The correct option is 3. The the of 7 bottles of brand B oil is $21 more than the price of 7 bottles of brand A oil.

Step-by-step explanation:

If a line passing through two points, then the equation of line is

y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)

From the given table it is clear that the graph of price of brand A oil is passing through (2,26) and (3,39). So, the equation model for price of brand A oil is

y-26=\frac{39-26}{3-2}(x-2)

y-26=13(x-2)

y-26=13x-26

y=13x

The required model for price of brand A oil is y =13x.

The price of 7 bottles of brand A is

y=13(7)=91

The required model for price of brand B oil is y =16x.

The price of 7 bottles of brand B is

y=16(7)=112

The difference between price of 7 bottles of brand A and brand B is

112-91=21

The the of 7 bottles of brand B oil is $21 more than the price of 7 bottles of brand A oil. Therefore the correct option is 3.

topjm [15]3 years ago
6 0
Brand A is y=13x
For x=7, brand B minus A is 16*7-13*7 = 21

How did you get 34?
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Before every​ flight, the pilot must verify that the total weight of the load is less than the maximum allowable load for the ai
ollegr [7]

Answer:

The probability that the aircraft  is  overload = 0.9999

Yes , The pilot has to be take strict action .

Step-by-step explanation:

P.S - The exact question is -

Given - Before every​ flight, the pilot must verify that the total weight of the load is less than the maximum allowable load for the aircraft. The aircraft can carry 37 ​passengers, and a flight has fuel and baggage that allows for a total passenger load of 6,216 lb. The pilot sees that the plane is full and all passengers are men. The aircraft will be overloaded if the mean weight of the passengers is greater than 6216/37 = 168 lb. Assume that weight of men are normally distributed with a mean of 182.7 lb and a standard deviation of 39.6.

To find - What is the probability that the aircraft is​ overloaded ?

         Should the pilot take any action to correct for an overloaded aircraft ?

Proof -

Given that,

Mean, μ = 182.7

Standard Deviation, σ = 39.6

Now,

Let X be the Weight of the men

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Probability that the aircraft is loaded be

P(X > 168 ) = P(\frac{x - \mu}{\sigma} > \frac{168 - \mu}{\sigma} )

                 = P( z > \frac{168 - 182.7}{39.6} )

                 = P( z > -0.371)

                 = 1 - P ( z ≤ -0.371 )

                 = 1 - P( z > 0.371)

                 = 1 - 0.00010363

                 = 0.9999

⇒P(X > 168) = 0.9999

As the probability of weight overload = 0.9999

So, The pilot has to be take strict action .

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