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Lady_Fox [76]
3 years ago
14

A store sells cooking oil of two different brands in bottles of the same size. The table below and the equation each show the pr

ice (y), in dollars, of different number of bottles of oil (x): Brand A Number of Bottles, x Price (dollars), y 2 26 3 39 4 52 5 65 Brand B y = 16x How many dollars more is the price of 7 bottles of brand B oil than the price of 7 bottles of brand A oil? $3 $10 $21 $29 my answer keeps coming out to 34
Mathematics
2 answers:
Strike441 [17]3 years ago
6 0

Answer:

The correct option is 3. The the of 7 bottles of brand B oil is $21 more than the price of 7 bottles of brand A oil.

Step-by-step explanation:

If a line passing through two points, then the equation of line is

y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)

From the given table it is clear that the graph of price of brand A oil is passing through (2,26) and (3,39). So, the equation model for price of brand A oil is

y-26=\frac{39-26}{3-2}(x-2)

y-26=13(x-2)

y-26=13x-26

y=13x

The required model for price of brand A oil is y =13x.

The price of 7 bottles of brand A is

y=13(7)=91

The required model for price of brand B oil is y =16x.

The price of 7 bottles of brand B is

y=16(7)=112

The difference between price of 7 bottles of brand A and brand B is

112-91=21

The the of 7 bottles of brand B oil is $21 more than the price of 7 bottles of brand A oil. Therefore the correct option is 3.

topjm [15]3 years ago
6 0
Brand A is y=13x
For x=7, brand B minus A is 16*7-13*7 = 21

How did you get 34?
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{4x-2y+5z=6 <br> {3x+3y+8z=4 <br> {x-5y-3z=5
lesya692 [45]

There are three possible outcomes that you may encounter when working with these system of equations:


  •    one solution
  •    no solution
  •    infinite solutions

We are going to try and find values of x, y, and z that will satisfy all three equations at the same time. The following are the equations:

  1. 4x-2y+5z = 6
  2. 3x+3y+8z = 4
  3. x-5y-3z = 5

We are going to use elimination(or addition) method

Step 1: Choose to eliminate any one of the variables from any pair of equations.

In this case it looks like if we multiply the third equation by 4 and  subtracting it from equation 1, it will be fairly simple to eliminate the x term from the first and third equation.

So multiplying Left Hand Side(L.H.S) and Right Hand Side(R.H.S) of 3rd equation with 4 gives us a new equation 4.:

4. 4x-20y-12z = 20      

Subtracting eq. 4 from Eq. 1:

(L.HS) : 4x-2y+5z-(4x-20y-12z) = 18y+17z

(R.H.S) : 20 - 6 = 14

5. 18y+17z=14

Step 2:  Eliminate the SAME variable chosen in step 2 from any other pair of equations, creating a system of two equations and 2 unknowns.

Similarly if we multiply 3rd equation with 3 and then subtract it from eq. 2 we get:

(L.HS) : 3x+3y+8z-(3x-15y-9z) = 18y+17z

(R.H.S) : 4 - 15 = -11

6. 18y+17z = -11

Step 3:  Solve the remaining system of equations 6 and 5 found in step 2 and 1.

Now if we try to solve equations 5 and 6 for the variables y and z. Subtracting eq 6 from eq. 5 we get:

(L.HS) : 18y+17z-(18y+17z) = 0

(R.HS) : 14-(-11) = 25

0 = 25

which is false, hence no solution exists



3 0
2 years ago
Integrate 1 - x / x(x2 + 1) d x by partial fractions.
solniwko [45]

Answer:

log x-\frac{log(x^{2}+1) }{2}-tan^{-1} x

Step-by-step explanation:

step 1:-   by using partial fractions

[tex]\frac{1-x}{x(x^{2}+1) } =\frac{A(x^{2}+1)+(Bx+C)(x }{x(x^{2}+1) }......(1)

<u>step 2:-</u>

solving on both sides

1-x=A(x^{2} +1)+(Bx+C)x......(2)

substitute x =0 value in equation (2)

1=A(1)+0

<u>A=1</u>

comparing x^2 co-efficient on both sides (in equation 2)

0 = A+B

0 = 1+B

B=-1

comparing x co-efficient on both sides (in equation 2)

<u>-</u>1  =  C

<u>step 3:-</u>

substitute A,B,C values in equation (1)

now  

\\\int\limits^ {} \, \frac{1-x}{x(x^{2}+1) } d x =\int\limits^ {} \frac{1}{x} d x +\int\limits^ {} \frac{-x}{x^{2}+1 }  d x -\int\limits \frac{1}{x^{2}+1 }  d x

by using integration formulas

i)  by using \int\limits \frac{1}{x}   d x =log x+c........(a)\\\int\limits \frac{f^{1}(x) }{f(x)} d x= log(f(x)+c\\.....(b)

\int\limits tan^{-1}x  dx =\frac{1}{1+x^{2} } +C.....(c)

<u>step 4:-</u>

by using above integration formulas (a,b,and c)

we get answer is

log x-\frac{log(x^{2}+1) }{2}-tan^{-1} x

6 0
3 years ago
Emily and Kate were at a cheerleading competition this fall.They cheered 12 rounds. Each round lasted 8.24 minutes. Calculate th
trapecia [35]

Answer:

98.88

Step-by-step explanation:

Given: They cheered 12 rounds. Each round = 8.24

To find the total number, multiply how much one round is with the total number of rounds.

  8.24

×     12

-----------

  1648

+ 8240

----------

98.88

Each girl cheered 98.88 minutes. If you need this estimated, the answer would be 99 minutes.

4 0
2 years ago
Midpoint (10,4) Endpoint (9,-4), find the coordinates of the other endpoint.​
mestny [16]

Answer:

(11, 12)

Step-by-step explanation:

<u>Mid point coordinates:</u>

  • x = (x₁ + x₂)/2
  • y = (y₁ + y₂)/2

<u>Since midpoint and one endpoint given (10, 4) and (9, -4), the other endpoint:</u>

  • x₂ = 2x - x₁ = 2*10 - 9 = 11
  • y₂ = 2y - y₁ = 2*4 - (-4) = 12

<u>So the other endpoint is: </u>(11, 12)

4 0
3 years ago
Which equation is graphed here?
choli [55]

Answer:

A

Step-by-step explanation:

because it is what i think its rright correct me!

3 0
3 years ago
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